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den301095 [7]
3 years ago
5

How is Newton’s 3rd law in baseball?

Physics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:Explanation: According to Newton's third law, the force exerted by the bat hitting the ball will be equal in magnitude but opposite in direction of the force the ball exerts on the bat. Generally, your arms are stiff when you hit the ball forward, so you will not feel the bat "recoiling".

Explanation:

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a 120 ohm resistor, a 60 ohm resistor, and a 40 ohm resistor are connected in parallel to a 120 volt power source. what is the c
Ber [7]
Answer:
\frac{1}{r \: total} = \frac{1}{120} + \frac{1}{60} + \frac{1}{40} \\ \frac{1}{r \: total} = \frac{1 + 2 + 3}{120} = \frac{6}{120} = \frac{1}{20} \\ r \: total = 20 \: ohms
Knowing V=ri
then, 120=i×20 --> i=6 A
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3 years ago
Consider this situation: A rope is used to lift an actor upward off the stage. Of the forces listed, identify which act upon the
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4 years ago
Read 2 more answers
Water drops from the nozzle of a shower onto the floor 81 inches below. The drops fall at regular intervals of time, the first d
Alexxx [7]

Answer:

0.91437 m

0.22859 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s=81\ inches=81\times 0.0254=2.0574\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.0574=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.0574\times 2}{9.81}}\\\Rightarrow t=0.64764\ s

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.64764}{3}\\\Rightarrow t'=0.21588\ s

For second drop time is given by

t''=2t'\\\Rightarrow t''=2\times 0.21588\\\Rightarrow t''=0.43176\ s

Distance from second drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.43176^2\\\Rightarrow s=0.91437\ m

Distance from second drop is 0.91437 m

Distance from third drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.21588^2\\\Rightarrow s=0.22859\ m

Distance from third drop is 0.22859 m

6 0
3 years ago
I need help on this question please answer within like a PLEASE QUICK HELP
Ludmilka [50]
The answer is c 5 starrrrrr
7 0
3 years ago
a rocket has a mass 250(10^3) slugs on earth. Specify its mass in si units and its weight in si unites. if the rocket is on the
Katena32 [7]

Answer:

W_{earth} = 35.74 * 10^6 N : Rocket weight on earth

W_{moon} = 5.91 * 10^6 N : Rocket weight on moon

Explanation:

Conceptual analysis

Weight is the force with which a body is attracted due to the action of gravity and is calculated using the following formula:

W = m × g Formula (1)

W: weight

m: mass

g: acceleration due to gravity

The mass of a body on the moon is equal to the mass of a body on the earth

The acceleration due to gravity on a body is different on the moon and on the earth

Equivalences

1 slug = 14.59 kg

Known data

m_{earth} = m_{moon} = 250 * 10^3 slug = 250* 10^3slug * \frac{14.59kg}{1slug} = 3647.5* 10^3 kg

g_{moon}= 1.62 \frac{m}{s^2}

g_{earth}= 9.8 \frac{m}{s^2}

Problem development

To calculate the weight of the rocket on the moon and on earth we replace the data in formula (1):

W_{earth} = 3647.5* 10^3 kg * 9.8 \frac{m}{s^2} = 35.74 * 10^6 N : Rocket weight on earth

W_{moon} = 3647.5* 10^3 kg * 1.62 \frac{m}{s^2} = 5.91 * 10^6 N : Rocket weight on moon

7 0
3 years ago
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