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Leni [432]
3 years ago
13

Saturn’s rings are composed of __________.

Physics
2 answers:
sineoko [7]3 years ago
8 0

Answer:

C

Explanation:

Misha Larkins [42]3 years ago
7 0

Answer:

lots of individual particles of ice and rock

Feedback: Although Saturn's rings appear solid when viewed from Earth, they are actually made of countless icy particles ranging in size from dust grains to small boulders.

Explanation:

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The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type
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c- Time

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A company has been hired to perform environmental remediation on an area of marshland. What would they most likely do?
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remove contamination; pollution ; test ground water and dirt .

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A student is watching waves come in from the ocean. He noticed that the first wave he saw (Wave A) had twice the amplitude of th
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Wave A

<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>

8 0
3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
Which is the best example of the use of imagery in a sentence?
Talja [164]

Answer:

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I hope it's helpful!

6 0
3 years ago
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