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KATRIN_1 [288]
3 years ago
10

A sounding rocket can generate a net upward force of 1,700 N of thrust during its 8 second burn. If the rocket has a mass of 200

kg at launch, what will be it’s average acceleration?
Physics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

The average acceleration of the rocket, a = 8.5 m/s²

Explanation:

Given that,

The upward force of the rocket, F = 1700 N

The time duration of rocket exerted the force, t = 8 s

The mass of the rocket, m = 200 Kg

The force exerted by the rocket is equal to the product of its mass and acceleration.

Therefore, the formula for force

                              <em> F = m x a</em>

                               a = F / m

Substituting the given values in the above equation

                                a = 1700 N / 200 Kg

                                   = 8.5 m/s²

Hence, the acceleration of the rocket is, a = 8.5 m/s²

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Hope this helps! :)

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Jean- Baptiste Say argued that entrepreneurs should be called the fourth factor of production because they
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Block 1, of mass m1 = 2.70 kg , moves along a frictionless air track with speed v1 = 27.0 m/s . It collides with block 2, of mas
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Answer:

a) Block 1 = 72.9kgm/s

Block 2 = 0kgm/s

b) vf = 1.31m/s

c) ∆KE = 936.36Joules

Explanation:

a) Momentum = mass× velocity

For block 1:

Momentum = 2.7×27

= 72.9kgm/s

For block 2:

Momentum = 53(0) (body is initially at rest)

= 0kgm/s

b) Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses of the block

u1 and u2 are their initial velocity

v is the common velocity

Given m1 = 2.7kg, u1 = 27m/s, m2 = 53kg, u2 = 0m/s (body at rest)

2.7(27)+53(0) = (2.7+53)v

72.9 = 55.7v

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Total KE before collision = 984.15Joules

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= 47.79Joules

∆KE = 984.15-47.79

∆KE = 936.36Joules

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