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REY [17]
2 years ago
15

A light ray traveling through a material with an index of refraction of 1.2 is incident on a material that has an index of refra

ction of 1.4. Compared to the incident angle, the refracted angle of the light ray is
Physics
1 answer:
zzz [600]2 years ago
3 0

Answer:

compared to the incident angle, the refracted angle is 45.56⁰

Explanation:

From Snell's law;

n₁sin(I) = n₂sin(r)

Where;

n₁ is the refractive index of light in medium 1 = 1.2

n₂ is the refractive index of light in medium 2 = 1.4

I is the incident angle

r is the refractive angle

n = \frac{1}{sin(I)}\\\\sin(I) = \frac{1}{n}\\\\sin(I) =\frac{1}{1.2}\\\\sin(I) =0.8333\\\\I = sin^-{(0.8333)

I = 56.439⁰

Applying snell's law

n_1sin(I) = n_2sin(r)\\\\sin(r) = \frac{n_1sin(I) }{n_2}\\\\sin(r) = \frac{1.2*sin(56.439) }{1.4}\\\\sin(r) = 0.714\\\\r = sin^-(0.714)\\\\r = 45.56^o

Therefore, compared to the incident angle, the refracted angle is 45.56⁰

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A fast Humvee drove from Desert A to Desert B. for the first 12 hours and traveled at an average speed of 185 km/h. For the next
FromTheMoon [43]

Answer:

The value is v_t = 172 \  km/h

Explanation:

From the question we are told that

    The average speed for the first 12 hours is u =  185 km/h

    The average speed for the next 13 hours is  v =  160 \ km/h

   

Generally the total time taken is mathematically represented as

     t_t =  12 + 13

=> t_t =  25 \  h

The distance covered in the first movement is

          D =  u * 12

         D =  185 * 12

        D =  2220 \  km

The distance covered in the first movement is

          d=  v * 13

         d =  160 * 13

        d =  2080 \  km

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