zero.
from newton's first law of motion
Answer:
I think D am not pretty show
Answer:
Magnitude of the average force exerted on the wall by the ball is 800N
Explanation:
Given
Contact Time = t = 0.05 seconds
Mass (of ball) = 0.80kg
Initial Velocity = u = 25m/s
Final Velocity = 25m/s
Magnitude of the average force exerted on the wall by the ball is given by;
F = ma
Where m = 0.8kg
a = Average Acceleration
a = (u + v)/t
a = (25 + 25)/0.05
a = 50/0.05
a = 1000m/s²
Average Force = Mass * Average Acceleration
Average Force = 0.8kg * 1000m/s²
Average Force = 800kgm/s²
Average Force = 800N
Hence, the magnitude of the average force exerted on the wall by the ball is 800N
Answer:
B, C, F
Explanation:
B: Sugar can be separated from the water by evaporating the water. This will leave large chunks of sugar.
C: Sugar gets spread out among the water.
F: Sugar water is a homogeneous <u>mixture. </u>Can't see the individual components because of the dissolving.
Hoped this helped! :)
