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Veseljchak [2.6K]
3 years ago
11

What is the acceleration of a car that slows down from 25.0 m/s to 10.0 m/s in 30 seconds? The car is traveling south.

Physics
1 answer:
lorasvet [3.4K]3 years ago
5 0
100 miles per hour ...........
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Bond [772]
<h2>If the object is moving then it has kinetic energy</h2>
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At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro
Feliz [49]

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

8 0
3 years ago
Which of these has components that can have a varying ratio?
Travka [436]
I say C. But I’m not 100% sure so check it first
6 0
3 years ago
3. What factors can contribute to an infant's ability to develop sensory competencies?
marta [7]

Answer:

Explanation:

Here's how to stimulate your baby's senses in age-appropriate ways:

Decorate the nursery with colorful, bold patterns. ...

Play hand games. ...

Use "baby talk." Studies have shown that the sing-song, fluctuating tones mothers use to talk to their babies are important for language development. ...

Hold your baby as much as possible.

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3 years ago
The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be
kap26 [50]

Answer:

v = 14.86 m/s

Explanation:

As we know that the force equation at the top is given as

\frac{mv^2}{R} = ma

now we know that

a_c = 1.5 g

so we have

\frac{v^2}{R} = 1.5 g

v = \sqrt{1.5 Rg}

so we will have

v = \sqrt{1.5(15)(9.81)}

v = 14.86 m/s

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