It becomes faster because there is less weight being pulled
Answer:
Explanation:
The change in momentum of the ball is equal to the impulse exerted on it, therefore:
where
is the change in momentum
F is the average force exerted on the ball
is the time during which the force is applied
In this problem,
F = 156 N
So, the change in momentum of the ball is
I’m sorry could you attach an image, I can not see the question
Answer:
a=7.384 m/s^2
Explanation:
let T be the tension in the string, m= mass
and a= acceleration
from the FBD in the attachment we can write
Tcos37°= mg
Tsin37° =ma
dividing both the equations we get
tan37° =a/g
therefore a=g×tan37°
a= 9.81×0.7535 = 7.384 m/s^2
the magnitude of the acceleration a of the train = 7.384 m/s^2
Answer:
Explanation:
Remark
At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.
Givens
h = 20 m
hd = 60 m
g = 9.81
vi = 0
Formula
d = vi*t + 1/2 a * t^2 We are solving for t
Solution
When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters
d = 0*t + 1/2 * 9.81 a* t^2
20 = 4.91 * t^2 Divide by 4.91
20/4.91 = 4.91 t^2 / 4.91
4.073 = t^2 Take the square root of both sides.
t = 2.02 seconds
Horizontal
d = 60 m
t = 2.02 seconds
v = ?
Note: there is no horizontal deceleration or acceleration
v = d/t
v = 60/2.02
Answer: v = 29.73 m/s