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PSYCHO15rus [73]

3 years ago

10

NH4NO3 (8) N20 (9) + H20 (1)

1 answer:

Ludmilka [50]3 years ago

3 0

Answer:

NH4NO3 = 1

N2O = 1

H2O = 2

Explanation:

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3 years ago

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A laboratory analysis of an unknown sample yields 74.0% carbon, 7.4% hydrogen, 8.6% nitrogen, and 10.0% oxygen. What is the empi

kirza4 [7]

Let us assume that there is a 100g sample present. The respective mass of each element will then be:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Now, we divide each constituent's mass by its Mr to obtain the moles of each
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
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O: (10 / 16) = 0.625
Dividing by the smallest number:
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3 years ago

Write the electron configuration for the following elements. (1) Neon, (2) Zinc, (3) Tungsten, (4) Magnesium

mash [69]

Explanation:

Hey there!!

We generally use s,p,d,f formula.

So, let's do with it.

1.Neon

Atomic no. = 10

So, Its electronic configuration is;

$= 1 {s}^{2} .2 {s}^{2} 2 {p}^{6}$

2.Zinc.

Atomic no. = 30

So, it's electronic configuration is;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}$

3. Tungsten.

Atomic no. = 74.

So, it's electronic configuration is;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6} 6 {s}^{2} 4 {f}^{14} 5 {d}^{4}$

4. Magnesium.

Atomic no. = 12

So, the electronic configuration is ;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2}$

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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4 years ago