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KiRa [710]
3 years ago
11

A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1

= 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Physics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

0.109  m/s

Explanation:

The calculation of the volume flow rate of the water is shown below:-

Av = Velocity (\pi)(Radius)^2

= 0.87(\pi)(0.2)^2

= 0.135258 m^3 / sec

= 0.109371429 m/s

or

= 0.109

So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come

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What is the net force on a car if the force of friction is 15 N and the forward force due to the engine is 20 N?
ICE Princess25 [194]
5 newton forward because the force of the engine is greater than the force of friction so that means the car is going forward.
You can think of this: when friction is greater than the force of an object its slowing down but when the force of the car is greater than the force of friction its speeding up.
Hope this helps
6 0
3 years ago
Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equ
sdas [7]

Answer:

x_{3}=2.35

Explanation:

Given x^2-2x-1=0,x_1=2

From Newton's method

x_{n+1}=x_n-\dfrac{f(x_n)}{f'(x_n)}

f(x)=x^2-2x-1

f'(x)=2x-2

Now

x_{2}=x_1-\dfrac{f(x_1)}{f'(x_1)}

f(x)=x^2-2x-1

f(2)=2^2-2\times 2-1

f(x)=-1

f'(2)=2x-2

f'(1)=2\times 2-2

f'(1)=2

x_{2}=2+\dfrac{1}{2}

x_{2}=2.5

x_{3}=x_2-\dfrac{f(x_2)}{f'(x_2)}

f(2.5)=2.5^2-2\times 2.5-1

f(2.5)=0.45

f'(2.5)=2\times 2.5-2

f'(2.5)=3

x_{3}=2.5-\dfrac{0.45}{3}

So

x_{3}=2.35

8 0
3 years ago
A lamp is connected to the power supply.
Vika [28.1K]

Answer:

There are 45 turns in the secondary coil.

Explanation:

Given that,

Input potential of the lamp, V_{in}=5\ V

The output potential of the lamp, V_{out}=1.5\ V

Number of turns in primary coil, N_P=150

We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\

So, there are 45 turns in the secondary coil.

5 0
3 years ago
The maximum amount of pulling force a truck can apply when driving on
kupik [55]
C the correct but not sure?
5 0
3 years ago
When the saw slices wood, the wood exerts a 104-N force on the blade, 0.128 m from the blade’s axis of rotation. If that force i
Soloha48 [4]

Answer:

Explanation:

When saw slices wood by exerting a force on the wood , wood also exerts a reaction force on the saw in opposite direction which is equal to the force of action that is 104 N.

So torque exerted by wood on the blade

= force x perpendicular distance from the axis of rotation

= 104 x .128

=13.312 Nm.

Since this torque opposes the movement of blade , it turns the blade slower.

5 0
3 years ago
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