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vagabundo [1.1K]
3 years ago
14

Which of the following systems is not true about machines?

Physics
1 answer:
pantera1 [17]3 years ago
8 0
Where are the options?
You might be interested in
Two charges are located in the xx – yy plane. If ????1=−4.25 nCq1=−4.25 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.0
Sati [7]

Answer:

Ex=  -17.1 N/C

Ey =  +26.9 N/C

Explanation:

We apply formula of electric field:

Ep=k*q/d²

Ep:  Electric field at point ( N/C)

q: Electric charge (C)

k: coulomb constant (N.m²/C²)

d: distance from charge q to point P (m)

In the attached graph we observe the directions of the electric field at P(0,0) due to q1 and q2

Calculation of the field at point P due to the load q₁

E₁=k*q₁/d₁² = 9*10⁹*4.25*10⁻⁹/1.080²= 32.8 N/C : Magnitude of E1

Direction of E₁ :Because the charge q₁ is negative the field enters the charge (+ y)

Calculation of the field at point P due to the load q₂

d_{2} = \sqrt{1.30^{2}+0.450^{2}  }

d₂=1.375 m

E₂=k*q₂/d₂² = 9*10⁹*3.80*10⁻⁹/ 1.375² = 18.09 N/C Magnitude of E₂

Direction of E₂ :Because the charge q₂ is positive the field leaves the charge in direction of angle β

, then,E₂ tiene componentes x-y  en P.

E₂x=-E₂cos β= -18.09*(1.3/1.375)= -17.1 N/C

E₂y=-E₂sin β= -18.09*(0.45/1.375)= -5.9 N/C

Calculation of the electric field at point P located at the origin(0,0)

Ex=E₂x= -17.1 N/C

Ey=E₁y+E₂y =32.8 N/C -5.9 N/C = 26.9 N/C

4 0
3 years ago
Calculate the heat gained by 100 grams of ice at -20°C in order to become water at 50°C. ( C = .5 for ice and C = 1 for water, Q
Korvikt [17]

Answer:

6008 cal

Explanation:

m_{i} = mass of ice = 100 g = 0.1 kg

c_{i}  = specific heat of ice = 0.5 cal/(kg°C)

c_{w}  = specific heat of water = 1 cal/(kg°C)

L  = Latent heat of fusion of ice = 80 J/g

T_{i}  = initial temperature of ice = - 20 °C

T_{f}  = final temperature of ice = 50 °C

Q = Heat gained

Heat gained is given as

Q = m_{i} c_{i}(0 - (T_{i}))+ m_{i}L + m_{i}c_{w}(T_{i} - 0)

Q = (100) (0.5) (0 - (- 20))+ (0.1)(80) + (100) (1)(50 - 0)

Q = 6008 cal

8 0
3 years ago
Why was nuclear energy first developed?
Helga [31]

Nuclear energy was not developed.  It has existed for as long as time has existed, that is, since the big bang.

The thing that was developed was humans' ability to USE nuclear energy, to do what we want it to do, when we want it to do it.

The reason this was first developed was to bomb the holy beans out of Japan, in order to win World War II.

Today (2020), nine of the world's nations are known to have 14,285 nuclear bombs in storage, for the same general purpose.  Seven of these nations are storing 1,170 of these bombs (about 8 percent), and the USA and Russia have all the rest ... 13,035 nuclear bombs.

All nine of these nations promise that they have no plan to use their bombs, they don't want to use them, it would be wrong and terrible to use them, and they will never be the first to use them, but they need to modernize their bombs so that theirs are better than anybody else's bombs, and they need to keep their bombs for as long as anybody else has any, and then maybe a little longer, just in case.

In the years after the ability to bomb the holy beans out of other people was developed, and enough equipment was built to do it 14 thousand times, the ability to use nuclear energy for other purposes was also developed.  It's used now to generate electrical energy, and to do several jobs in Medical science.  

7 0
3 years ago
What are the differences between glaciers and geysers
liq [111]

A glacier is frozen and a geyser has boiling water coming from it. A glacier is usually still but it sometimes breaks and a geyser erupts. Also geysers are mostly rare and glaciers aren't.

7 0
3 years ago
Find the instantaneous acceleration at t=ls for an object moving along a straight axis with velocity function:
Maru [420]
The answer is A.
Explanation:
We know that the average acceleration a for an interval of time Δt is expressed as:

a = Δv
Δt
where Δv is the change in velocity that occurs during Δt.
e formula for the instantaneous acceleration a is almost the same, except that we need to indicate that we're interested in knowing what the ratio of Δv to Δt approaches as Δt approaches zero.

We can indicate that by using the limit notation.

So, the formula for the instantaneous acceleration is:

a = lim Δv
Δt→0 Δt
8 0
3 years ago
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