What force is needed to accelerate a 0.5kg football at a rate of 40m/s

The cube with 2.00m wide and 2.00m long and 2.00m high has a weight of 960.00 N what pressure does it exert

andre [41]

2m X 2m = 4m ^2
960n / 4 = 240pa

3 0

3 years ago

A basketball player makes a jump shot. The 0.599 kg ball is released at a height of 2.18 m above the floor with a speed of 7.05

7nadin3 [17]

Answer:

$W_{drag} = 4.223\,J$

Explanation:

The situation can be described by the Principle of Energy Conservation and the Work-Energy Theorem:

$U_{g,A}+K_{A} = U_{g,B} + K_{B} + W_{drag}$

The work done on the ball due to drag is:

$W_{drag} = (U_{g,A}-U_{g,B})+(K_{A}-K_{B})$

$W_{drag} = m\cdot g\cdot (h_{A}-h_{B})+ \frac{1}{2}\cdot m \cdot (v_{A}^{2}-v_{B}^{2})$

$W_{drag} = (0.599\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.18\,m-3.10\,m)+\frac{1}{2}\cdot (0.599\,kg)\cdot [(7.05\,\frac{m}{s} )^{2}-(4.19\,\frac{m}{s} )^{2}]$

$W_{drag} = 4.223\,J$

7 0

4 years ago

Read 2 more answers

A particle with charge q and momentum p, initially moving along the x-axis, enters a region where a uniform magnetic field* B=(B

VMariaS [17]

Answer:

Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

Explanation:

So, from the question, we are given that the charge = q, the momentum = p.

=> From the question We are also given that, "initially, there is movement along the x-axis which then enters a region where a uniform magnetic field* B = (B0)(k) which then extends over a width x = L, the distance = d in the +y direction as it traverses the field."

Momentum,P = mass × Velocity, v -----(1).

We know that for a free particle the magnetic field is equal to the centrepetal force. Thus, we have the magnetic field = mass,.m × (velocity,v)^2 / radius, r.

Radius,r = P × v / B0 -----------------------------(2).

Centrepetal force = q × B0 × v. ----------(3).

(If X = L and distance = d)Therefore, the radius after solving binomially, radius = (d^2 + 2 L^2) / 2d.

Equating Equation (2) and (3) gives;

P = B0 × q × r.

Hence, the Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

4 0

3 years ago

Solar cell A produces 100 joules of energy, when a light source is shown on it for 3 minutes. Solar cell B produces 200 joules o

ella [17]

Answer: (B). Solar cell B, because it generates more power.

Explanation:

Given that,

For solar cell A

Energy = 100 Joules

Time = 3 minutes = 180 sec

Power of cell A

Power = Energy/Time

$P = \dfrac{100}{180}\ Watt$

$P = 0.55\ Watt$

For solar cell B

Energy = 200 joules

Time = 5 minutes = 300 sec

Power of cell B

Power = Energy/Time

$P = \dfrac{200}{300}\ watt$

$P = 0.66\ Watt$

Hence, Solar cell B, because it generates more power.

3 0

3 years ago

Read 2 more answers

Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha

Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

$n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}$

It means she can send 52 oranges and it is maximum quantity.

4 0

3 years ago