Answer:
hola me llamo bruno y tu?
Explanation:
pero yo soy de mexico
<span>If the force is fn, then it acting on the block, in the term of f2 and the other variables of the problems. then we assume the surface is rest on it's rigid, then the magnitude of the force is,
fn =f2 sin(?) +m g</span>
The length to which the pendulum will be adjusted to keep perfect time is 29.59 inches. See the explanation below.
<h3>What is the justification for the above answer?</h3>
T1 = 2πR√(L1/GM)
and
T2 = 2πR√(L1/GM)
T1/T2 = √(L1/L2).
If the pendulum has an efficient period, that means it executes with perfect frequency.
Thus,
T2 = (24 * 60)/x
= 1440/x
This means that in one day, there are perfect cycles of represented by "x". Note that there are 1440 minutes in one day.
If the other Pendulum is slower by 10 minutes, that means
T1 = 1450/x
Hence
(1450/x)/(1440/x) = √(L1/L2).
⇒ 1450/1440 = √(L1/L2).
Thus,
(1450/1440)² = 30/L
L = 30/(1450/1440)²
L = 30/(1.00694444444)²
L = 30/1.01393711419
L = 29.5876337695
L
29.59 inches.
Hence, the pendulum will need to be adjusted by 29.59 inches to ensure that the clock keeps perfect time.
Learn more about pendulum problems:
brainly.com/question/16617199
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Answer:
The induced emf can be found by Faraday’s Law.


The magnetic field is increasing at a rate of 0.1T/s. So,

Finally,

Explanation:
Faraday’s Law states that a change in the magnetic flux induces an emf in the circuit. The magnetic flux is the multiplication of magnetic field and the area of the loop. The area of the loop is simple, and the change of magnetic field as a function of time is given in the question.
The minus sign in front of the Faraday’s Law means that the induced current always opposes the change of the magnetic flux. Since we do not know the direction of the magnetic field in this question, we cannot find the direction of the induced emf on the loop.