Answer:
10 m
Explanation:
Weight = 10 N
mg = 10
m = 10 / 10 = 1 kg
g = 10 m/s^2
Initial mechanical energy = 40 J
Final mechanical energy = 140 J
change in total energy = 140 J – 40 J = 100 J
At the maximum vertical height, the velocity = 0 m/s
So,it has only potential energy at maximum height
P = m x g x h
100 = 1 x 10 x h
h = 10 m
The particles in diagram 3 move fast enough to break away from each other.
This Question is incomplete.The complete question is
Combustion gases enter a gas turbine at 627∘C and 1.2 MPa at a rate of 2.5 kg/s and leave at 527∘C and 500 kPa. It is estimated that heat is lost from the turbine at a rate of 20 kW. Using air properties for the combustion gases and assuming the surroundings to be at 25∘C and 100 kPa, determine (a) the actual and reversible power outputs of the turbine. (b) the exergy destroyed within the turbine, and (c) the second-law efficiency of the turbine.
Answer:
(a) W=257.5kW Wrev=367.3kW
(b) X=109.8kW
(c) n=0.7
Explanation:
For Part(a)
Actual power output is determined from the energy balance. The final and initial enthalpy are taken from A-17 for the given temperature
mh₁=W+Q+mh₂
W=m(h₁-h₂)-Q
W=2.5(939.93-821.95)-20
W=257.5kW
The reversible power output is determined from the rate of energy destruction
Wrev=W+X
Wrev=W+T₀(m(s₂-s₁-Rln(p₂/p₁)+Q/T₀)
Wrev=257.5+298( 2.5 (2.71787-2.84856-0.287*ln(500/1200)+20/298)
Wrev=367.3kW
For part(b)
X=Wrev-W
X=367.3-257.5
X=109.8kW
For part (c)
Second-law efficiency is determined from the ratio of the actual and reversible power output:
n=W/Wrev
n=257.5/367.3
n=0.7
Answer:
Explanation:
Let the amplitude of individual wave be I and resultant amplitude be 1.703 I . Let the phase difference be Ф in terms of degree
From the formula of resultant vector
(1.703I)² = I² + I² + 2 I² cosФ
2.9 I² = 2I² + 2 I² cosФ
.9I² = 2 I² cosФ
cosФ = .9 / 2
= .45
Ф = 63.25 .
The central maximum
extends to the first minimum on either side.
So the first minimum
occurs at <span>3cm / 2 = 1.5cm = 0.015m to the side from the center of the
central maximum. </span>
<span>Now using the formula,
λ = a(y/L)</span>
Where a is the width of
the slit, y = distance of first minimum from center, L = distance of screen
from slit, and λ = wavelength of the light that strikes a single slit at normal
incidence which is unknown here.<span>
a = L x λ/y
a = 1.80 m x (λ / 0.015 m)
a = 120 λ </span>
<span>Use the value of λ for
any light and you get the width of slit.</span>