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Papessa [141]
3 years ago
12

HELPPP!!!! if you double the force what is the change in acceleration

Physics
1 answer:
jenyasd209 [6]3 years ago
8 0

As we know that acceleration is directly proportional to force, therefore as the force is doubled, acceleration gets doubled too.

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Examples of applied force
Vladimir [108]

Answer:

Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)

Pull - You can apply a force by directly pulling on an object (like pulling a wagon)

Explanation:

4 0
3 years ago
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which has a greater speed a heron hat travels 600m in 60 seconds or a duck that travels 60 m in 5 seconds? Explain
erma4kov [3.2K]
The duck at 12m/s has a greater speed than the heron which travels at 10m/s
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Which is greater the attraction of the earth for 1 kg of aluminum or aluminum or attraction of 1kg of aluminum for the earth?
OleMash [197]
Those forces are exactly equal.

Gravity always works as a pair of <em>EQUAL</em> forces ... one in each direction
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8 0
3 years ago
Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest
mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

Where

\lambda represents wavelength

R represents Rydberg's constant

n_f represents Final energy states

and n_i represents initial energy states

Now Substitute is

1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

now we will put the values into the above formula

= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )

= 1218888.889 m^{-1}

Now we will rewrite the answer in the term of \lambda

\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m

So, the whole Paschen series is in the part of the spectrum.

8 0
3 years ago
How much force is needed to accelerate a 1245 kg car at a rate of 4.25<br> m/sec^2?
BartSMP [9]

Answer:

F = 5291.25 N

Explanation:

F = Ma so 1245 times 4.25^2 ,, that equals 5291.25 N

3 0
2 years ago
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