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Nat2105 [25]
3 years ago
7

The work of Subrahmanyan Chandrasekhar is likely to have been most influenced by the work of which of the following scientists?

A. Albert Einstein B. Edwin Hubble C. Marie Sklodowska-Curie D. Lord Kelvin
Physics
2 answers:
Alex73 [517]3 years ago
7 0

Edwin Hubble  ---apex

borishaifa [10]3 years ago
3 0

Answer

Correct Answer is B(Edwin Hubble)

Explantion

The work of Subrahmanyan Chandrasekhar is likely to have been most influenced by Edwin Hubble because both have worked in the feild of astrophysics.

Subrahmanyan Chandrasekhar was an astrophysicist. He belons to India. He is known for his work on the theoretical structure and evolution of stars. Subrahmanyan Chandrasekhar with William Fowler won the Nobel Prize in Physics in 1983 largely for this early work. He has worked in many other areas within theoretical physics and astrophysics.

Edwin Hubble was an astronomer who belongs to America. He is known for Hubble Law. Hubble discovered that many objects which was thought to be clouds of dust and gas  were actually galaxies beyond the Milky Way. He has an important contribution in establishing the fields of observational cosmology and extra galactic astronomy


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kakasveta [241]

Question:

A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?

Answer:

Time for the race will be t = 9.26 s

Explanation:

Given data:

As the sprinter starts the race so initial velocity = v₁ = 0

Distance = s₁ = 20 m

Acceleration = a = 4.20 ms⁻²

Distance = s₂ = 100 m

We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.

Using 3rd equation of motion

(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)

v₂ = 12.96 ms⁻¹

Time for 20 m distance = t₁ = (v₂ - v ₁)/a

t₁ = 12.96/4.2 = 3.09 s

He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be

Time for 100 m distance = t₂ = s₂/v₂

t₂ = 80/12.96 = 6.17 s

Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s

T = 9.26 s

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A car with a mass of 2.0 * 10^3 kg is traveling at 15 m/s. what is the momentum of the car?
Allushta [10]
Hello,


Your answer to this problem is 400/3


Hope this helps!
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