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3 years ago

if you divide a force measured in newtons by a speed measured in in meters per second in what units will the answer be expressed

Physics

1 answer:

Tcecarenko [31]3 years ago

8 0

'Newton' is [ kg·m/s² ].

So if you divide Newtons by [ m/s ], it goes something like this:

(kg·m/s²) / (m/s) =

(kg·m/s²) · (s/m) =

(kg·m·s / m·s²) =

kilogram / second .

This is an interesting exercise in manipulating units, but it doesn't seem to mean anything in the real world.

We performed one meaningless operation ... dividing force by speed ... and ended up with another quantity that has no physical significance ... kilogram per second.

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The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What

Romashka [77]

The formula we need to use is displacement.

$d=\Delta{x}=x_f-x_i$ , where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

$2=5-x_i\Longrightarrow x_i=3$ .

So the initial position of truck A is 3.

Hope this helps.

r3t40

8 0

2 years ago

Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.

jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d - I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L = (μI/2π) x (I/2d + I/d)

F₃/L = (μI/2π) x (3I/2d)

F₃/L = 3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

6 0

2 years ago

Select ALL of the following that are vector quantities.

Dahasolnce [82]

Answer:

166 kg *m/s

44 N upward

39 m/s east

Explanation:

The short answer: If it has direction, it's a vector.

The long answer:

Vectors, unlike scalars, have direction. The first one, 166 kg*m/s is momentum, since momentum is velocity*mass, and velocity is a vector, momentum must be a vector.

44 Newtons is a vector since it has direction, in this case, upward. Force is acceleration*mass, and since acceleration is a vector, force must be a vector.

39 m/s is velocity, velocity has a direction, therefore it's a vector.

13.7 grams is mass since mass doesn't change with direction, it's a scalar, the opposite of a vector.

86 miles per hour has speed, but speed has no direction, therefore it's a scalar.

12 meters is distance, distance has no direction, therefore it's a scalar.

6 0

2 years ago

If you are soaking wet and the water on your clothes evaporates, you will feel cold. Explain the cooling effect in the terms of

Georgia [21]

Explanation:

Evaporation requires energy in order to break up intermolecular forces and excite water molecules (fast-moving gas molecules vs. slower moving liquid molecules). Therefore when the water in the wet clothes evaporates, it is drawing away some heat from your body (the surroundings

6 0

2 years ago

a 1.00kg piece of aluminum metal at 90 degrees Celsiusis placed in 4 L (=4.00kg)of water at 25°C determine the final temperature

vovikov84 [41]

From the basic "heat lost by hot object=heat gained by colder object" principle, we have
m1c1ΔT1=m2c2ΔT2
where m1= 1kg
m2=4kg
c1=900J/kg k
c2=4200J/kg k
With this information at hand we have
m1c1(90-T)=m2c2(T-25)
after substituting the given values we can find that
T=28.3^{0}c

7 0

2 years ago