12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.
Answer:
Explanation:
conjugate acid, based on Brønsted–Lowry acid–base theory, is a chemical compound that is formed by the reception of a proton by a base
a. CH₃COOH + H₂O ⇌ H₃0⁺ + CH₃C00-
Acid <> CH₃COOH
Base <> H₂O
Conjugate acid <> H₃0 +
Conjugate base <>CH₃C00-
b. HCO₃ + H₂O ⇌ H₂CO₃⁻ + OH⁻
Acid <> H₂O
Base <> HCO₃
Conjugate acid <> H₂CO₃⁻
Conjugate base <>OH⁻
C. HNO₃ + SO₄²⁻ ⇌ HSO₄⁻ + NO₃⁻
Acid <>HNO₃
Base <>SO₄²⁻
Conjugate acid <>HSO₄⁻
Conjugate base <>NO₃⁻
A Bronsted acid is reffered to as a proton donor while a Bronsted base is a proton acceptor
Henry's law constant for oxygen is 0,0013 mol/L·<span>atm. Air has 21,0% oxygen.
concentration of oxygen at 1 atm: 0,0013 mol/L</span>·atm · 0,21 · 1 atm = 0,000273 mol/l.
concentration of oxygen at 1 atm: 0,0013 mol/L·atm · 0,21 · 0,892 atm = 0,000243 mol/l.
difference in concentration: 0,000273 - 0,000243 = 0,00003 mol/L.
n(oxygen) = 0,00003 mol/L · 4,40 L = 0,000132 mol.
C. The thermometer reads 100
