When the reaction equation is:
HF ↔ H+ + F-
and when the Ka expression
= concentration of products/concentration of reactions
so, Ka = [H+][F-]/[HF]
when we assume:
[H+] = [F-] = X
and [HF] = 0.35 - X
So, by substitution:
6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X
∴ X = 0.015 M
∴[H+] = X = 0.015
when PH = -㏒[H+]
∴PH = -㏒0.015
= 1.8
First, find the total mass.
34.5 g + 18.2 g + 2.6 g = 55.3 g
Divide the mass of each element by total mass.
34.5 g / 55.3 g = .62 x 100 = 62% element a
18.2 g / 55.3 = .33 x 100 = 33% element b
2.6 g / 55.3 = .047 x 100 = 4.7% element c
Hope I helped!
1. rancidification fixation of water is CHEMICAL CHANGE
2. Tearing of paper is PHYSICAL CHANGE
3. Rusting if iron is CHEMICAL CHANGE
4. Electrolysis of water is CHEMICAL CHANGE
Answer:
Shiny like a limousine
You're spending like a cash machine
Smile, show your golden teeth
That's how you cover up your cavities
You're glowing like a diamond ring
I saw you bought some other things
You're spending like a cash machine
To cover up your insecurities
Don't front, no needExplanation:
3455
