Answer:
12 moles of H₂O are formed in this combustion.
Explanation:
First of all, think the reaction:
2CH₃OH (l) + 3O₂ (g) → 2CO₂ (g) + 4H₂O (g)
Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂
We have 9 moles of O₂, so this is the limiting reactant.
3 mol of oxygen produce 4 mol of water
Then, 9 mol of oxygen will produce ( 9 .4)/3 = 12 moles
To calculate this, we need the Molarity formula. This formula tell us that Molarity, which is a concentration unit, is equal to the number of moles divided by the volume. In this question we already have the Molarity and the Volume, so let's build our equation:
C = n/V (You can see Molarity with the letter "C" because it means concentration)
3 = n/1
n = 1 * 3
n = 3 moles of NaOH
Hey there!:
Molar mass MgCl2 = 95.2110 g/mol
So:
1 mole MgCl2 -------------- 95.2110 g
moles MgCl2 ---------------- 319 g
moles MgCl2 = 319 * 1 / 95.2110
moles MgCl2 = 319 / 95.2110
=> 3.350 moles of MgCl2
Hope that helps!
The answer is God because if you think on it hard enough, you realize that we couldnt of come from nowhere. Then, you get a headache and just stop thinking about.
Hope this helps :D
