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disa [49]
2 years ago
6

Which is a shorter process - (circle one) selective breeding or natural selection?

Chemistry
1 answer:
Wewaii [24]2 years ago
6 0

Selective breeding is a shorter process because it can produce the desired traits in the amount of time it takes to conceive and give birth to a particular organism whereas natural selection requires several generations to achieve the desired traits. Selective breeding can be controlled within one generation meanwhile natural selection requires more variation.

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Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the
NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' =  Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0
3 years ago
Not able to be separated by physical means but is chemical what is it
Ray Of Light [21]
My science text book said that it was either diamond or gold.  Gold may not be right, but I am pretty sure diamond is.

Sorry if I got this wrong.
8 0
2 years ago
Which is the smallest?<br> A) 1.3 x 1020<br> B) 2.9 x 1021<br> C) 9.5 x 1032<br> d) 8.4 x 1019
alexgriva [62]
Answer: A, 1.3*1020, 1326

A. 1326

B. 2960.9

C. 9804

D. 8559.6
7 0
3 years ago
Read 2 more answers
sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction
prisoha [69]

Answer:

2.76 × 10⁻¹¹  

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

                         C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹:       0         0         -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

\text{The relationship between $\Delta G^{\circ}$ and K  is}\\\Delta G^{\circ} = -RT \ln K

T = (25.0 + 273.15) K = 298.15 K

\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}

3 0
3 years ago
When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
Trava [24]
1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
.
C10H8  +  12O2  ---->  10CO2   + 4H2O

C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
6 0
3 years ago
Read 2 more answers
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