<span>V = 150.0 mL = 0.15 L
c = 1.70 M
</span>m=?
For the purpose, the equation for molar concentration is necessary:
c=n/V
From the equation we can determine the number of moles:
n= cxV = 1.70M x 0.15L = 0.255 mole
Now we can calculate the mass:
m = nxM = 0.255 x 119= 30.34 g is necessary
Answer:
The energy of photon is 20.22×10⁻¹⁷ J
Explanation:
Given data:
Frequency of photon = 3.05×10¹⁷ Hz
Energy of photon = ?
Solution:
Formula:
E = hf
h = planck's constant = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3.05×10¹⁷ Hz
Hz = s⁻¹
E = 20.22×10⁻¹⁷ J
Thus, the energy of photon is 20.22×10⁻¹⁷ J
Answer:
![m_{H_2O}=9.24gH_2O](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D9.24gH_2O)
Explanation:
Hello there!
In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:
![m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2} *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D40.0gNa_O_2%2A%5Cfrac%7B1molNa_O_2%7D%7B78gNa_O_2%7D%2A%5Cfrac%7B2molH_2O%7D%7B2molNa_O_2%7D%20%20%2A%5Cfrac%7B18.02gH_2O%7D%7B1molH_2O%7D%20%5C%5C%5C%5Cm_%7BH_2O%7D%3D9.24gH_2O)
Best regards!