I think it is poor stability
Molar solubility of AgCl will be 0.59 × M.
The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.
A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.
Calculation of molar solubility:
Given data:
M = 0.30 M
= 1.77 ×
The reaction can be written as:
AgCl ⇔
s s (s+0.30)
= [ ]+ []
1.77 × = s (0.30)
s = 1.77 × / 0.3
s = 0.59 × M
Therefore, molar solubility of AgCl will be 0.59 × M.
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Answer: Massive
Explanation: There are many galaxies out in the universe and it's possible they go on indefinitely. Out of all of these, our solar system is very very tiny. As an analogy, our universe would be like an atom which are the the smallest units of matter. There are many other galaxies that we just haven't been able to discover but they are there.
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
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Answer:
The formula would be: C₆H₈O
Explanation:
The mass of carbon dioxide formed = 627.4 mg
The percentage of carbon in the sample would be:
% carbon =
Where
44 is the molar mass of carbon dioxide.
The percentage of hydrogen in the sample would be:
% Hydrogen =
Rest will be oxygen = 100 -[74.92+8.33]=16.75
Let us calculate the moles of each of the elements present:
moles of carbon =
moles of hydrogen =
moles of oxygen =
The mole ration of carbon, hydrogen and oxygen = C:H:O = 6 : 8 : 1
so the formula would be:
C₆H₈O