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sergejj [24]
3 years ago
12

Discuss how the following factors determine the rate of electron transfer in biological systems:

Chemistry
1 answer:
Cloud [144]3 years ago
3 0

Answer:check explanation

Explanation:

(a). HOW THE DISTANCE BETWEEN ELECTRON DONOR AND ACCEPTOR AFFECTS THE RATE OF ELECTRON TRANSFER IN BIOLOGICAL SYSTEM:

Distance between the acceptor and the donor can affect in two ways; short distance and long distance effect.

Short distance causes

electronic orbitals of donor and acceptor directly overlap whereas in LONG DISTANCE reactions this coupling is indirect because of

sequential overlaps of atomic orbitals of the donor, the intervening medium, and the orbitals of the acceptor.

(b). HOW REORGANIZATION ENERGY OF REDOX ACTIVE SPECIE SURROUNDING MEDIUM AFFECTS:

the reorganized energy does not depend on the pre-existing intra molecule electric field. The charge transferred inside the molecule interacts with its aqueous surroundings.

Reorganized energy can be calculated using Poisson-Boltzmann equation.

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Which of the following is ignored when determining the relative mass of atoms? (2 points)
QveST [7]
The atomic mass is determined by the number of protons and neutrons in a atoms for example oxygen has eight protons and neutrons which gives oxygen and atomic mass of 16
8 0
3 years ago
In an experiment, a student wants to increase the rate of a reaction that involves gases. Which change to the reactants would
Rainbow [258]

Answer:

  • The last option: <u><em>Decrease the volume to increase pressure and to increase concentration.</em></u>

Explanation:

You can support your choice on basis of the collision theory.

According to the collision theory, the chemical reactions happen when the molecules collide with each other, in the correct orientation and with enough kinetic energy to overcome the activation energy.

As consequence, the larger the number of collisions the larger the rate of a reaction.

In the case of a reaction that involves gases, decreasing the volume, will increase the pressure and the concentration (volume is inversely related to both the pressure and the concentration) causing the molecules to be closer to each other and to collide with higher frequency, this is you will expect more collisions, and so an increase on the rate of the reaction. That is expressed by the last choice: decrease the volumen to increase pressure and to increase concentration.

3 0
3 years ago
It is a very easy matter. I want the solution please
Helga [31]

Answer:

0.125

Explanation:

For 250 ml it is 0.5 moles. If you know the Molecular weight of NaCl you multiply with 0.5 to get the answer. Required number of moles =2⋅0.25=0.5 moles.

4 0
2 years ago
Help in apex!!!!
GenaCL600 [577]
<h3><u>Answer</u>;</h3>
  • Halogens
  • Alkali metals
<h3><u>Explanation</u>;</h3>
  • Elements in the periodic table are classified into various categories including alkali metals, alkaline-earth metals, halogens, and noble gases among others.
  • <u>Alkali metals are Group 1 elements in the periodic table.</u> They comprise of elements lithium (Li) through francium (Fr). They have similar characteristics and behavior.
  • <u>Halogens is another category of elements which is a subset of the nonmetals.</u> They comprise group 17 of the periodic table, from fluorine (F) through Astatine (At). These elements are chemically reactive and reacts with other elements such as group 1 and group 2 element.
4 0
3 years ago
When 50.0 mL of 1.00 M HCl(aq) and 50.0 mL of 1.00 M NaOH(aq) , both at 22.0 °C, are added to a coffee cup calorimeter, the temp
Igoryamba

Answer:

The heat produced by this reaction is 2887J

Explanation:

The reaction of HCl with NaOH occurs as follows:

HCl + NaOH → H2O + NaCl + ΔH

<em>Where ΔH is released heat due the reaction</em>

<em />

The equation of a coffee cup calorimeter is:

Q = C*m*ΔT

<em>Where Q is heat produced, </em>

<em>C is specific heat of the solution (4.18J/g°C), </em>

<em>m is mass of the solution (50mL + 50mL = 100mL = 100g -Because density is 1g/mL) </em>

<em>and ΔT is change in temperature (28.9°C - 22.0°C = 6.9°C)</em>

<em />

Replacing:

Q = 4.184J/g°C*100g*6.9°C

Q = 2887J

The heat produced by this reaction is 2887J

<em />

5 0
3 years ago
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