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4 years ago

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En una báscula hidráulica colocamos una persona de 75 kg sobre un émbolo y un camión de 7200 kg sobre una plataforma de 5 m de l

argo por 2,5 m de ancho. Si entre ambos se establece el equilibrio, ¿Cuál es el diámetro del émbolo?

1 answer:

TEA [102]4 years ago

4 0

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A nonconducting ring with a radius of 11.5 cm is uniformly charged with a total positive charge of 10.0 µC. The ring rotates at

zhuklara [117]

Answer:

$B=1.21*10^{-10}T$

Explanation:

The magnitude of the magnetic field on the axis of the ring is given by:

$B=\frac{\mu_0 IR^2}{2(r^2+R^2)^{\frac{3}{2}}}(1)$

$\mu_0$ is the permeability of free space, $I$ is the flowing current through the ring, $R$ is the ring's radius and $r$ is the distance to the center of the ring.

The flowing current through the ring is defined as the ring's charge divided into the time taken by the charge to complete one revolution, that is, the period $T=\frac{2\pi}{\omega}$ . So, we have:

$I=\frac{q}{T}\\I=\frac{q}{\frac{2\pi}{\omega}}\\\\I=\frac{\omega q}{2\pi}\\I=\frac{18\frac{rad}{s}(10*10^{-6}C)}{2\pi}\\I=2.87*10^{-5}A$

Now, replacing in (1):

$B=\frac{(4\pi*10^{-7}\frac{T\cdot m}{A})(2.87*10^{-5}A)(0.115m)^2}{2((0.05m)^2+(0.115m)^2)^{\frac{3}{2}}}\\B=1.21*10^{-10}T$

6 0

4 years ago

An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal.

Hitman42 [59]

Answer:

(a) max. height = 3.641 m

(b) flight time = 1.723 s

(c) horizontal range = 31.235 m

(d) impact velocity = 20 m/s

Above values have been given to third decimal. Adjust significant figures to suit accuracy required.

Explanation:

This problem requires the use of kinematics equations

v1^2-v0^2=2aS .............(1)

v1.t + at^2/2 = S ............(2)

where

v0=initial velocity

v1=final velocity

a=acceleration

S=distance travelled

SI units and degrees will be used throughout

Let

theta = angle of elevation = 25 degrees above horizontal

v=initial velocity at 25 degrees elevation in m/s

a = g = -9.81 = acceleration due to gravity (downwards)

(a) Maximum height

Consider vertical direction,

v0 = v sin(theta) = 8.452 m/s

To find maximum height, we find the distance travelled when vertical velocity = 0, i.e. v1=0,

solve for S in equation (1)

v1^2 - v0^2 = 2aS

S = (v1^2-v0^2)/2g = (0-8.452^2)/(2*(-9.81)) = 3.641 m/s

(b) total flight time

We solve for the time t when the vertical height of the object is AGAIN = 0.

Using equation (2) for vertical direction,

v0*t + at^2/2 = S substitute values

8.452*t + (-9.81)t^2 = 3.641

Solve for t in the above quadratic equation to get t=0, or t=1.723 s.

So time for the flight = 1.723 s

(c) Horiontal range

We know the horizontal velocity is constant (neglect air resistance) at

vh = v*cos(theta) = 25*cos(25) = 18.126 m/s

Time of flight = 1.723 s

Horizontal range = 18.126 m/s * 1.723 s = 31.235 m

(d) Magnitude of object on hitting ground, Vfinal

By symmetry of the trajectory, Vfinal = v = 20, or

Vfinal = sqrt(v0^2+vh^2) = sqrt(8.452^2+18.126^2) = 20 m/s

7 0

4 years ago

If the boy and his bike actually had a mass of 40 kg instead of 50 kg how much force would it take for him to accelerate at 0.8

klio [65]

Answer:

F = 32 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N] (units of Newtons)

m = mass = 40 [kg]

a = acceleration = 0.8 [m/s²]

Now replacing:

$F=m*a\\F = 40*0.8\\F = 32 [N]$

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3 years ago

NEEED HELP!!!! A hurricane warning has been issued in a location in Florida. What would people in the location most likely do?

siniylev [52]

Head to states farther inland.

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3 years ago

Read 2 more answers

A parallel beam of light from a laser with a wavelength 450 nm, falls on a grating whose slits are 1.28 x 10^-4 cm apart. How fa

Katena32 [7]

Answer:

Y_1 = 1.195 m = 119.5 cm

Explanation:

For nth order bright fringe, the distance from the center of the pattern is given by :-

$Y_n = \frac{n\lambda D}{d}.$

Where,

n = order of nth bright fringe. = 1

$\lambda =$ wavelength of given light = $450 nm = 450*10-{9} m$

D = distance between the screen and slits. = 3.4 m

and d = separation between the slits. $= 1.28 *10^{-4} cm =1.28 *10^{-6} m$

$Y_1 = \frac{(1 *450 *10{-9} *3.4)}{(1.28*10{-6})}$

Y_1 = 1.195 m = 119.5 cm

7 0

3 years ago