What kind of radiation is emitted in the following nuclear reaction
1 answer:
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So, If the resistance decreases, then the current increases. Assume voltage is constant.
If the voltage increases, then the current increases. Assume resistance is constant.
Explanation:
According to the ohm's law; I = V/R;
- If the resistance decreases the current increases assuming that the voltage is constant
- if the voltage increases, then the current increases assuming that the resistance is constant.
Based on Ohm's law, we know that the current through a metallic conductor is directly proportional to the voltage across the ends.
From the relationship;
I =
we see that V = IR
These equations affirms that
- If the resistance decreases the current increases assuming that the voltage is constant based on the second equation
- if the voltage increases, then the current increases assuming that the resistance is constant based on the first equation.
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Answer:
q = 1.96 10⁴ C
Explanation:
The elective force is given by
= q E
Where E is the electric field and q the charge.
Let's use Newton's law of equilibrium for the case of the suspended drop
F_{e} –W = 0
F_{e} = W
q E = m g
q = m g / E
Let's calculate
q = 2.0 10⁵ 9.8 / 100
q = 1.96 10⁴ C