We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km
Answer:
5.25 m
Explanation:
Given;
The height equation h;
h=-x^2+3x+3
Where;
h = the height above water
x = horizontal distance from the end of the board
The maximum height is at h' = 0, when change in h with respect to change in x is equal to zero.
differentiating the equation h.
dh/dx = h' = -2x + 3 = 0
Solving for x;
2x = 3
x = 3/2
Substituting into the function h;
h max = -x^2+3x+3
h max = -(3/2)^2 + 3(3/2) +3 = -9/4 +9/2 +3 = 9/4 + 3 =
h max = 21/4 = 5.25 m
Answer:
The last part on the right side of the diagram
Explanation:
Im on plato and just got it right :)
Answer:
The plane would need to travel at least
(
.)
The
runway should be sufficient.
Explanation:
Convert unit of the the take-off velocity of this plane to
:
.
Initial velocity of the plane:
.
Take-off velocity of the plane
.
Let
denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation
.
Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration
times average velocity
.
The distance that the plane need to cover would be:
.
The primary job of a(n) ____
is to increase the power of a modified radio wave.
Answer:
<h2>amplifier</h2>
Explanation:
Hope it helps:)
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