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Zolol [24]
3 years ago
8

The following label was found on a bottle of liquid hydrocarbons in the laboratory of Dr. Ima Turkey following his disappearance

under mysterious circumstances. Although the name defines a structure unambiguously, it is not the correct IUPAC substitutive name. Give the correct name for the compound. Details count; pay attention to hyphens, commas, and spelling.
2-ethyl-2,4,6-trimethylheptane

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0

If you draw the given compound you would see that the longest chain have 8 carbons, so the compound is octone not heptane.

Now you give indices for each carbon atom involved in the principal carbon chain in such a way the substituents are heaving the lowest number.

The correct name of the compound is:

2,4,6,6-tetramethyl-octane

In the attached figure you may see the drawing of the molecule.

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Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO
Irina-Kira [14]

Answer : The enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of H_2SO_4 will be,

S+H_2+2O_2\rightarrow H_2SO_4    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) S+O_2\rightarrow SO_2     \Delta H_1=-298.2

(2) SO_2+\frac{1}{2}O_2\rightarrow SO_3    \Delta H_2=-98.2

(3) SO_3+H_2O\rightarrow H_2SO_4    \Delta H_3=-130.2

(4) H_2+\frac{1}{2}O_2\rightarrow H_2O    \Delta H_4=-285.8

Now adding all the equations, we get the expression for enthalpy of formation of H_2SO_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)

\Delta H=-812.4kJ/mol

Therefore, the enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

3 0
3 years ago
Is sand an element or a compound?
Romashka-Z-Leto [24]
Neither

its a mixture
7 0
3 years ago
Which of the following is the correct measurement for the volume of liquid shown below?
mr Goodwill [35]

Answer:

A. 3.5ml

Explanation:

lowest point of liquid or meniscus

5 0
3 years ago
Why is it that you can not feel earths movement but you can observes its effects
ss7ja [257]
The correct answer would be we have no other frame of reference besides the sky. We could actually tell we are moving because of the shifting of stars in the sky over time. But really, “A” would be your answer. We have the same momentum of the earth. It’s like being on a train at a constant speed. The only way you know you’re moving is if you look out the window or the speed changes causing you to be pushed around. Same thing with earth, our only reference is the sky
5 0
3 years ago
Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple
AfilCa [17]

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha. Whereas a neutron is represented by a symbol ^{1}_{0}n, that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

        ^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n

5 0
3 years ago
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