The position of a particle along a straight-line path is defined by s=(t3−6t2−15t+7) ft, where t is in seconds. part a part comp
1 answer:
A) The position of the particle along the straight-line path is given by
where t is the time.
If we substitute t=11 s inside the equation, we find the total distance covered during this time, in feet:
which converted into meters is s=182 m.
b) The average velocity of the particle at t=11 s is equal to the total distance travelled, s=597 ft, divided by the time taken, t=11 s:
We can also calculate it in meters/second:
where t is the time.
If we substitute t=11 s inside the equation, we find the total distance covered during this time, in feet:
which converted into meters is s=182 m.
b) The average velocity of the particle at t=11 s is equal to the total distance travelled, s=597 ft, divided by the time taken, t=11 s:
We can also calculate it in meters/second:
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1)
2) 2418 rad/s
3)
4) 36.3 m/s
Explanation:
1)
The angular acceleration of an object in rotation is the rate of change of angular velocity.
It can be calculated using the following suvat equation for angular motion:
where:
is the angular displacement
is the initial angular velocity
t is the time
is the angular acceleration
In this problem we have:
is the angular displacement
t = 1.3 ms = 0.0013 s is the time elapsed
is the initial angular velocity
Solving for , we find:
2)
For an object in accelerated rotational motion, the final angular speed can be found by using another suvat equation:
where
is the initial angular velocity
t is the time
is the angular acceleration
In this problem we have:
t = 1.3 ms = 0.0013 s is the time elapsed
is the initial angular velocity
is the angular acceleration
Therefore, the final angular speed is:
3)
The tangential acceleration is related to the angular acceleration by the following formula:
where
is the tangential acceleration
is the angular acceleration
r is the distance of the point from the centre of rotation
Here we want to find the tangential acceleration of the tip of the claw, so:
is the angular acceleration
r = 1.5 cm = 0.015 m is the distance of the tip of the claw from the axis of rotation
Substituting,
4)
Since the tip of the claw is moving by uniformly accelerated motion, we can find its final speed using the suvat equation:
where
u is the initial linear speed
a is the tangential acceleration
t is the time elapsed
Here we have:
(tangential acceleration)
u = 0 m/s (it starts from rest)
t = 1.3 ms = 0.0013 s is the time elapsed
Substituting,
Answer:
hello your question is incomplete attached below is the complete question
answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor i.e. J > Jm
Explanation:
Gear ratio G > 1
a) Determine the moment of inertia felt by the motor
moment of inertia felt by Motor = moment of Inertia at the armature
b) Determine the moment of inertial felt by someone who is rotating the mass by hand
moment of inertia felt by someone is = J
The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor
attached below is a detailed solution
