Answer:
The work done against gravity is 78.4 J
Explanation:
The work is calculated by multiplying the force by the distance that the
object moves
W = F × d, where W is the work , F is the force and d is the distance
The SI unit of work is the joule (J)
We need to find the work done against gravity when lowering a
16 kg box 0.50 m
→ F = mg
→ m = 16 kg, and g = 9.8 m/s²
Substitute these value in the rule
→ F = 16 × 9.8 = 156.8 N
→ W = F × d
→ F = 156.8 N and d = 0.50
Substitute these values in the rule
→ W = 78.4 J
<em>The work done against gravity is 78.4 J</em>
m = mass of water in bathtub = 62.7 kg
= initial temperature of water in tub = 31 c
M = mass of water added = ?
= initial temperature of water added = 76 c
T = final equilibrium temperature of the system = 40.3 c
c = specific heat of water = 4186
Using conservation of heat
Heat gained by water in tub = Heat lost by water added
m c (T - ) = M c ( - T)
m (T - ) = M ( - T)
(62.7) (40.3 - 31) = M (76 - 40.3)
M = 16.3 kg
Answer:
Condensation is the change of water from its gaseous form water vapor into liquid water.
Explanation:
Answer:d= 0.0219m
Explanation:
P= force /area
Area =πr^2=πd^2/4
πd^2/4=force/pressure
πd^2/4=34/90000
πd^2/4=0.0003778
πd^2= 0.0003778*4
πd^2=0.001511
Since π=3.142
d^2= 0.001511/3.142
d^2= 0.000480
d= square root of 0.000480
d= 0.0219m