There is a step-up transformer that doubles the voltage. If the primary coil has a voltage of 10 V, what will the voltage in the

Question

4 years ago

8

secondary coil be?

1 answer:

Rufina [12.5K] · Answer 1 · 2022-03-04T11:36:21+03:00

The voltage in the secondary coil is 20 V

Explanation:

The transformer equation gives the relationship between the voltage in the primary and secondary coil of a transformer:

$\frac{V_p}{N_p}=\frac{V_s}{N_s}$

where

$V_p$ is the voltage in the primary coil

$V_s$ is the voltage in the secondary coil

$N_p$ is the number of turns in the primary coil

$N_s$ is the number of turns in the secondary coil

It can also be rewritten as

$\frac{V_s}{V_p}=\frac{N_s}{N_p}$

In this problem, we have a step-up voltage that doubles the voltage, so:

$\frac{V_s}{V_p}=2$

The voltage in the primary coil is 10 V,

$V_p = 10 V$

Therefore, the voltage in the secondary coil is

$V_s = 2V_p = 2(10)=20 V$

Learn more about potential difference:

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