Answer:
The potential at the center of the sphere is -924 V
Explanation:
Given;
radius of the sphere, R = 0.22 m
electric field at the surface of the sphere, E = 4200 N/C
Since the electric field is directed towards the center of the sphere, the charge is negative.
The Potential is the same at every point in the sphere, and it is given as;
-------equation (1)
The electric field on the sphere is also given as;
![E = \frac{1}{4 \pi \epsilon _o} \frac{|q|}{R^2}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon%20_o%7D%20%5Cfrac%7B%7Cq%7C%7D%7BR%5E2%7D)
![|q |= 4 \pi \epsilon _o} R^2E](https://tex.z-dn.net/?f=%7Cq%20%7C%3D%20%204%20%5Cpi%20%5Cepsilon%20_o%7D%20R%5E2E)
Substitute in the value of q in equation (1)
![V = \frac{1}{4 \pi \epsilon_o} \frac{-(4 \pi \epsilon _o R^2E)}{R} \ \ \ \ q \ is \ negative\ because \ E \ is\ directed \ toward \ the \ center\\\\V = -RE\\\\V = -(0.22* 4200)\\\\V = -924 \ V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon_o%7D%20%5Cfrac%7B-%284%20%5Cpi%20%5Cepsilon%20_o%20R%5E2E%29%7D%7BR%7D%20%5C%20%5C%20%5C%20%5C%20q%20%5C%20is%20%5C%20negative%5C%20because%20%5C%20E%20%5C%20is%5C%20directed%20%20%5C%20toward%20%5C%20the%20%5C%20center%5C%5C%5C%5CV%20%3D%20-RE%5C%5C%5C%5CV%20%3D%20-%280.22%2A%204200%29%5C%5C%5C%5CV%20%3D%20-924%20%5C%20V)
Therefore, the potential at the center of the sphere is -924 V