<u>Answer:</u> The ideal yield of carbon dioxide is 7.506 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of carbon monoxide = 5.61 g
Molar mass of carbon monoxide = 28 g/mol
Putting values in equation 1, we get:

The chemical equation for the reaction of carbon monoxide and water follows:

By Stoichiometry of the reaction:
1 mole of carbon monoxide produces 1 mole of carbon dioxide
So, 0.200 moles of carbon monoxide will produce =
of carbon dioxide
Now, calculating the mass of carbon dioxide from equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 0.200 moles
Putting values in equation 1, we get:

To calculate the experimental yield of carbon dioxide, we use the equation:

Percentage yield of carbon dioxide = 85.3 %
Theoretical yield of carbon dioxide = 8.8 g
Putting values in above equation, we get:

Hence, the ideal yield of carbon dioxide is 7.506 grams