Alpha particles bouncing off of gold foil.
Answer:
The answer to your question is P = 1.357 atm
Explanation:
Data
Volume = 22.4 L
1 mol
temperature = 100°C
a = 0.211 L² atm
b = 0.0171 L/mol
R = 0.082 atmL/mol°K
Convert temperature to °K
Temperature = 100 + 273
= 373°K
Formula

Substitution

Simplify
(P + 0.0094)(22.3829) = 30.586
Solve for P
P + 0.0094 = 
P + 0.0094 = 1.366
P = 1.336 - 0.0094
P = 1.357 atm
Answer:
Erm.......... can you clarify what "paper", you just said "paper" there's a lot.
Explanation:
I’m guessing you mean moles. So the big M stands for mol/L. That means first you’d want to convert your mL to L. To do this write your 250mL then make parenthesis for the conversion. 1L=1000mL
250mL(1L/1000mL). Since the mL is on the bottom in the parenthesis we can cancel them out. Now all we do is divide and keep the L.
.250L is what you get. Now we need to figure out how to cancel the L with what we have left. We know M stands for Moles/L so this means in order to get ride of L we need to multiply our new number times the 1.5
.250L X 1.5 moles
_______
1L
This gives us 0.375 moles NH4SO4
Answer:

Explanation:
Hello!
In this case, when performing mathematical operations with numbers in scientific notation, the first step is to write them in standard notation:
550 - 65.0
Thus, the result without any significant figures-based analysis is:
615.0
However, since 550 is significant to the ones and 65.0 to the tenths, we need to round the result to the bigger significance, in this case to the ones; therefore the appropriate result would be:
615
That in scientific notation would be:

Best regards!