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Liula [17]
3 years ago
10

The plank is 5.1 meters long and has a mass of 9.2 kg, ack has a mass of 93.6 kg, and Diane has a mass of 64.2 kg. Assuming Dian

e sits at one end of the plank, how far from his end of the plank should Jack sit for the two of them to be perfectly balanced?

Physics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

The answer is 0.8 m

Explanation:

According the attached diagram, if we take the momentum in the point 0:

\frac{m_{D}*5.1 }{2} =m_{J} *X

Where

mD = mass of Diane = 64.2 kg

mJ = mass of Jack = 93.6 kg

Replacing:

X=\frac{\frac{64.2*5.1}{2} }{93.6} =1.75m

\frac{L}{2} -X=Y=\frac{5.1}{2} -1.75\\Y=0.8m

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FromTheMoon [43]

Answer:

Option (A) is correct.

Explanation:

A horizontal rope has a length of 5 m and a mass of 0.00145 kg. If a pulse occurs on this string, generating a wavelength of 0.6 m and a frequency of 120 Hz. The tension to which the string is subjected is

mass of string, m = 0.00145 kg

Frequency, f = 120 Hz

wavelength = 0.6 m

Speed = frequency x wavelength

speed = 120 x 0.6 = 72 m/s

Let the tension is T.

Use the formula

v =\sqrt\frac{T L}{m}\\\\72 = \sqrt\frac{T\times 5}{0.00145}\\\\T = 1.5 N

Option (A) is correct.

7 0
3 years ago
A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has
irga5000 [103]

Answer:

The total linear acceleration is approximately 0.246 meters per square second.

Explanation:

The total linear acceleration (a) consist in two components, <em>radial</em> (a_{r}) and <em>tangential</em> (a_{t}), in meters per square second:

a_{r} = \omega^{2}\cdot r (1)

a_{t} = \alpha \cdot r (2)

Since both components are orthogonal to each other, the total linear acceleration is determined by Pythagorean Theorem:

a = \sqrt{a_{r}^{2}+a_{t}^{2}} (3)

Where:

r - Radius of the wheel, in meters.

\omega - Angular speed, in radians per second.

\alpha - Angular acceleration, in radians per square second.

Given that wheel accelerates uniformly, we use the following kinematic equation:

\omega = \omega_{o}+ \alpha\cdot t (4)

Where:

\omega_{o} - Initial angular speed, in radians per second.

t - Time, in seconds.

If we know that r = 0.1\,m, \alpha = 2\,\frac{rad}{s^{2}}, \omega_{o} = 0\,\frac{rad}{s} and t = 0.60\,s, then the total linear acceleration is:

\omega = \omega_{o}+ \alpha\cdot t

\omega = 1.2\,\frac{rad}{s}

a_{r} = \omega^{2}\cdot r

a_{r} = 0.144\,\frac{m}{s^{2}}

a_{t} = \alpha \cdot r

a_{t} = 0.2\,\frac{m}{s^{2}}

a = \sqrt{a_{r}^{2}+a_{t}^{2}}

a \approx 0.246\,\frac{m}{s^{2}}

The total linear acceleration is approximately 0.246 meters per square second.

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3 years ago
N2O is the chemical formula of a covalent compound used in the production of whipping cream. The elements that make up this comp
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podryga [215]

Explanation:

For a circular orbit v= \sqrt{\frac{G.m}{r} } with G = 6.6742 × 10^{-11}

Given m = 6.42 x 10^23 kg and  r=9.38 x 10^6 m

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A parallel plate capacitor is created by placing two large square conducting plates of length and width 0.1m facing each other,
borishaifa [10]

Answer:

8.854 pF

Explanation:

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Let K be the dielectric constant.

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C = 8.854 pF

5 0
3 years ago
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