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Liula [17]
3 years ago
10

The plank is 5.1 meters long and has a mass of 9.2 kg, ack has a mass of 93.6 kg, and Diane has a mass of 64.2 kg. Assuming Dian

e sits at one end of the plank, how far from his end of the plank should Jack sit for the two of them to be perfectly balanced?

Physics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

The answer is 0.8 m

Explanation:

According the attached diagram, if we take the momentum in the point 0:

\frac{m_{D}*5.1 }{2} =m_{J} *X

Where

mD = mass of Diane = 64.2 kg

mJ = mass of Jack = 93.6 kg

Replacing:

X=\frac{\frac{64.2*5.1}{2} }{93.6} =1.75m

\frac{L}{2} -X=Y=\frac{5.1}{2} -1.75\\Y=0.8m

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A baseball has a mass of 145 g. A bat exerts a force of 18,400 N on the ball. What is the acceleration of the ball?
nekit [7.7K]

By definition, we have to:

F = m * a

Where,

F: force [N]

m: mass of the object [Kg]

a: acceleration of the object [m / s ^ 2]

Clearing the acceleration we have:

a = \frac{F}{m}

Substituting values we have:

a = \frac{18400}{0.145}\\a = 126896.5517

Rounding the nearest whole we have:

a = 126897 \frac{m}{s^2}

Answer:

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a = 126897 \frac{m}{s^2}

4 0
3 years ago
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Jada was walking home for 30 mins. How fast was she walking, if her house is 4 km away fron school?
earnstyle [38]

Answer:

8 km an hour (about 5mph)

Explanation:

It depends on what you are looking for because there is no unit specified, but if you want kilometers an hour then all you have to do is multiply both sides by 2.

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3 0
3 years ago
At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant accele
EleoNora [17]

Answer:

306.8264448 m

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Explanation:

t = Time taken

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In order to overtake both distances should be equal

\dfrac{1}{2}at^2=ut\\\Rightarrow \dfrac{1}{2}at=u\\\Rightarrow t=\dfrac{2u}{a}\\\Rightarrow t=\dfrac{2\times 23.5}{3.6}\\\Rightarrow t=13.056\ s

s_c=\dfrac{1}{2}at^2\\\Rightarrow s_c=\dfrac{1}{2}3.6\times 13.056^2\\\Rightarrow s_c=306.8264448\ m

The distance the car has to travel is 306.8264448 m

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 3.6\times 306.8264448+0^2}\\\Rightarrow v=47.0016\ m/s

The speed of the car when it overtakes the truck is 47.0016 m/s

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