This is called a "substitution problem" is where you have variable that have defined values and plug them in value calculate the expression.
B = 3m + 2p # Starting equation
2 = (3)(5) + 2p # Substitution
2 = 15 + 2p # Multiplication
-13 = 2p # Subtract 15 from both sides
= p # Divide both sides from 2
p =
# Use the reflexive property of equality
Hope this helps!
Step 1 distribute the 5 across (8+0.2)
6^3+5(8+0.2)
6^3+40+1
6^3+41 (<em>I simplified the +40 and the +1</em>)
Step 2 take 6 to the power of 3
6^3+41
6x6x6 6x6=36 36x6=216
216+41 (<em>Simplify!</em>)
257
I hope this helped!
It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :
X(X-1)(X-2)(X-3)(X-4)(X-5)(X+1)(X+2)(X+3)= X^9-9X^8+6X^7+126X^6-231X^5-441X^4+944X^3+324X^2-720X
This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5
And it has 3 negative zeros : - 1, -1, - 3
And it has 0 as a zero too.
There is also this one :
(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144
It has 4 positive zeros : 1, 2, 3, 4.
It has complex zeros : i and - i
3 negative zeros : - 1, - 2 , - 3
Good Luck
Answer:
The expression 6x should be 6x^2.
Step-by-step explanation:
Given is the chart of multiplication of the binomial by the trinomial.
Let's check each element in the chart:-
3x times x^2 = 3x^3
3x times 2x = 6x^2
3x times 4 = 12x
2 times x^2 = 2x^2
2 times 2x = 4x
2 times 4 = 8
From the given chart, we can identify that <u>6x should be 6x^2.</u>
Hence. option B is correct, i.e. The expression 6x should be 6x^2.