Answer:
The answer is 7.8 kJ / mol.
Explanation:
Energy = (number of methyl group) (Gauche interactions)(3.8kJ/mol per interaction)
= (2)(2)(3.8 kJ / mol)
= 15.2 kJ / mol.
The energy = (number of methyl group) - ( energy of gauche interactions)
= (23 kJ/mol) - 15.2 kJ/mol
= 7.8 kJ / mol.
1 millimetre is 0.001 metre.
1 metre is 1,000 millimetres.
Answer:
3.83×10¯⁴ N
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +2.4x10¯⁸ C
Charge 2 (q₂) = +1.8x10¯⁶ C
Distance apart (r) = 1.008 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
The magnitude of the electrical force acting between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²
F = 0.0003888 / 1.016064
F = 3.83×10¯⁴ N
Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N
B is correct.
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V = 60km/h
S=500km
t = ?
v = S/t
t = S/v
t = 500km / 60 km/h
t ≈ 8,33 h
