Answer:
HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)
Explanation:
From the question given above
HNO₃ + H₂O —> ?
Nitric acid, HNO₃ reacts with water, H₂O to form aqueous solution of nitric acid as illustrated below:
HNO₃ + H₂O —> HNO₃ (aq)
Nitric acid is a strong acid and, so will ionised completely when dissolved in water. This is illustrated below:
HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)
Answer:
air gas
diamond solid
copper solid
candle wax solid or melted would be liquid
Explanation:
Answer:
<h2>The sequence is; b, e, a, d, c
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Explanation:
1. In a decomposition reaction; One reactant is broken down into two or more than two products is called decomposition.
2. A combustion reaction; A fuel is combined with oxygen to produce carbon dioxide and water, this reaction is called combustion reaction.
3. A synthesis reaction; it occurs when two or more reactants combine to form one product is known as synthesis reaction.
4. Double Replacement Reaction; Two compounds react to form two different compounds is known as double Replacement Reaction.
5. A single replacement reaction; occurs when a compound reacts with an element to form a new compound , this reaction is called as single replacement reaction.
Answer:
The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1
Explanation:
According to the consideration, let us first find the ratio of S and O in both the compounds
For SO:
Let us express it as

For SO₂,
Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

Let us express it as

Now, for the ratio of both the above-calculated ratios,

The required ratio is 2:1
Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where V- volume , T - temperature and k - constant

parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

V = 251 mL
the new volume is 251 mL