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Rama09 [41]
3 years ago
12

Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p

roduced. Calculate the number of moles of bromine liquid produced. Round your answer to significant digits.
Chemistry
1 answer:
masha68 [24]3 years ago
6 0

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, (Br_2) = 159.8 g/mol

Putting values in above equation, we get:

\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol

Hence, the amount of liquid bromine produced is 4.79 moles.

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1. Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

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Number of mole NaCl =.?

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Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

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3. Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

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Number of mole = Mass /Molar Mass

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Mole of C6H12O6 = 66.67 moles

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Mole of Br2 = 3.5x10^-5 moles

Mass of Br2 =?

Mass = number of mole x molar Mass

Mass of Br2 = 3.5x10^-5 x 160

Mass of Br2 = 5.6x10^-3 = 0.0056g

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