A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is
1 answer:
We have the equation of motion , where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement
Here final velocity, v = 40m/s
Initial velocity, u = 0 m/s
Displacement s = 2 m
Substituting
So the baseball pitcher accelerates at 400m/ to release a ball at 40 m/s.
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Answer:
The torque is 0.31 Nm.
Explanation:
Electrical energy, E = 8400 J
time, t = 1 min
Angular speed, w = 2900 rpm = 303.53 rad/s
efficiency = 2/3 of input power
The toque is given by
As here it is given that
x = 150 m
a= 2 m/s^2
now initial speed of the plane must be zero as it start from rest
now we will use kinematics
so its final speed is maximum 24.5 m/s
so it will not reach to desired speed at the end of runway