Question

A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is it?

Answer 1

We have the equation of motion $v^2=u^2+2as$, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement

Here final velocity, v = 40m/s

        Initial velocity, u = 0 m/s

        Displacement s = 2 m

Substituting $40^2=0^2+2*a*2\\ \\ a=400m/s^2$

So the baseball pitcher accelerates at 400m/$s^2$ to release a ball at 40 m/s.