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Tresset [83]
3 years ago
6

A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is

it?
Physics
1 answer:
Reil [10]3 years ago
4 0

We have the equation of motion v^2=u^2+2as, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement

Here final velocity, v = 40m/s

        Initial velocity, u = 0 m/s

        Displacement s = 2 m

Substituting 40^2=0^2+2*a*2\\ \\ a=400m/s^2

So the baseball pitcher accelerates at 400m/s^2 to release a ball at 40 m/s.

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Which of the following lies in the ecliptic plane?
babymother [125]
<h2>Answer: Earth's orbital path around the Sun</h2><h2></h2>

The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>

<u />

It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about 23\° approximately. This is due to the inclination of the Earth's axis.

Hence, the correct option is Earth's orbital path around the Sun.

7 0
4 years ago
A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0
FromTheMoon [43]

Answer:

v_0 =1.71

Explanation:

the parabolic movment is described by the following equation:

y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2

Finally, solving for v_0, we get:

v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}

v_0 =1.71

4 0
4 years ago
Two long, parallel wires are separated by a distance of 2.50 cm. The force per unit length that each wire exerts on the other is
Kisachek [45]

Answer:

The current in the second wire is 8.33 A and the two currents are flowing in the opposite directions

Explanation:

Given that,

The separation between two long parallel wires, d = 2.5 cm

The force per unit length that each wire exerts on the other is, \dfrac{F}{l}=4\times 10^{-5}\ N/m

The current in one wire, I_1=0.6\ A

(a) The force per unit length of the wire is given by :

\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}

On putting all the values we get :

4\times 10^{-5}=\dfrac{4\pi \times 10^{-7}\times 0.6I_2}{2\pi \times (2.5\times 10^{-2})}

I_2=8.33\ A

So, the current in the second wire is 8.33 A.

(b) It is given that, both the wires repel each other, so the current in other wire is flowing in the opposite direction of the current in the first wire.

Hence, this is the required solution.

6 0
3 years ago
a blank is the small number to the lower right of the chemical symbol. It tells how many atoms of the element are present in the
victus00 [196]
The answer is subscript
4 0
4 years ago
A train can travel at 200 mph. How long will it take you to get to Chicago if it is 1800 miles away?
labwork [276]
The answer is d, 9 hours
5 0
3 years ago
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