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sweet-ann [11.9K]
3 years ago
11

11. Fill in the blanks below for a general chemical reaction (products, reactants).

Chemistry
1 answer:
Bad White [126]3 years ago
5 0
Reactants on the left and products on the right
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Which describes density?
Yuri [45]

Answer:

Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre. ... For example, the density of air is 1.2 kilograms per cubic metre.

4 0
3 years ago
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How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

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3 years ago
How did the growth of the economy affect the status of women society?
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3 years ago
Which of the following tells you the number of molecules in 1 mole of a gas?
Nezavi [6.7K]

Answer:

Avogrado's number

Explanation:

It's unniversal measure of moles

7 0
3 years ago
Safrole was once used as a flavoring in root beer, until it was banned in 1960. what is the vapor pressure of a solution prepare
BartSMP [9]
Answer is: 48,25 torr.
Raoult's Law: p = x(solv) · p(solv)
p - <span>vapour pressure of a solution.
</span>x(solv) - <span>mole fraction of the solvent.
</span>p(solv) - <span>vapour pressure of the pure solvent.
</span>n(ethanol) = 950g ÷ 46,07g/mol = 20,62 mol.
x(solv) = moles of solvent ÷ total number of moles
x(solv) = 20,62 ÷ 21,77 = 0,965.
p = 0,965 ·50,0 torr = 48,25 torr.

4 0
3 years ago
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