A chemist who studies water samples did a demonstration of how to test for lead in water. She added a clear solution of potassiu

Question

3 years ago

7

m iodide to a clear solution of lead nitrate. Then a yellow swirling solid formed in the liquid. What is most likely true about the yellow solid?

2 answers:

evablogger [386] · Answer 1 · 2022-05-05T16:40:08+03:00

8 0

<em>I actually need help myself with question and no one has helped me yet ? </em>

Lerok [7] · Answer 2 · 2022-05-05T14:55:22+03:00

Answer:

The swirling yellow solid formed is lead iodide (PbI₂).

Explanation:

The reaction of potassium iodide (KI) with lead nitrate (Pb(NO₃)₂) will produce lead iodide (PbI₂) and potassium nitrate (KNO₃) according to the equation:

2KI + Pb(NO₃)₂ → PbI₂↓ + 2KNO₃

Lead iodide (PbI₂) is a yellow swirling precipitate that is formed from the reaction.