Question

A chemist who studies water samples did a demonstration of how to test for lead in water. She added a clear solution of potassium iodide to a clear solution of lead nitrate. Then a yellow swirling solid formed in the liquid. What is most likely true about the yellow solid?

Answer 1

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Answer 2

Answer:

The swirling yellow solid formed is lead iodide (PbI₂).

Explanation:

• The reaction of potassium iodide (KI) with lead nitrate (Pb(NO₃)₂) will produce lead iodide (PbI₂) and potassium nitrate (KNO₃) according to the equation:

2KI + Pb(NO₃)₂ → PbI₂↓ + 2KNO₃

• Lead iodide (PbI₂) is a yellow swirling precipitate that is formed from the reaction.