Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?

Physics

1 answer:

ozzi3 years ago

6 0

Answer: The forces acting on both of them will increase in magnitude.

Explanation:

According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.

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If you know that the universe is estimated to be 14 billion years old . what is the age of the universe in seconds ???? (knowing

Svetlanka [38]

Answer:

<em>The estimated age of the universe is</em> $4.42*10^{17}\ seconds$

Explanation:

<u>Time Units Conversion</u>

Sometimes we need to express magnitudes in different units, depending on the specific situation handled in the question or problem at hand. Magnitudes like length, time, mass, temperature, pressure, etc., can be expressed in several different units.

The most common units for time are years, months, days, hours, minutes, and seconds. There are 3,600 seconds in one hour and 24 hours in one day.

We are given the estimated age of the universe as 14 billion solar years. If one solar year is 365.25 days long, then the age, expressed in days is

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Some quantities need to be expressed in scientific notation. This is the case since the numbers are too high

$14,000,000,000 * 365.25 = 5.1135*10^{12}\ days$

There are 24*3600=86400 seconds in one day, so

$5.1135*10^{12}\ days=5.1135*10^{12} * 86400 =4.42*10^{17}\ seconds$

The estimated age of the universe is $4.42*10^{17}\ seconds$

6 0

3 years ago

Read 2 more answers

How do you calculate the net force when there are multiple forces in different directions?

Artyom0805 [142]

To find $F_{net}$ we need to use vector addition and use the x and y components. First we subtract vector 2 from vector 5 which results in a vector with a length of 3 pointing directly east, then we use the distance formula to find the length of the net force $F_{net} = \sqrt{(3)^2+(4)^2} \\$ which gives $F_{net} = 5$ . We now have a magnitude but we also need a direction, since vector 4 and vector 5 are perpendicular. Using $\theta = \tan^{-1} (\frac{4}{3})$ where tan^-1(y/x) we get an angle of 53 degrees. The resultant force vector is 5 distance with an angle of 53 degrees north east.