Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
1 answer:
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Answer:
Explanation:
Let x₀ be the amplitude , ω be the angular velocity
velocity at displacement x ,
v = ω
at
v = ω [
v² = ω² x
1/2 m v²
= 3/8 m x ω²x₀²
Total energy = 1/2 m ω²x₀²
Kinetic energy as fraction of total energy
= 3/8 m x ω²x₀² x 2 / m ω²x₀²
= 3 / 4
Fraction of potential energy
= 1 - 3/4
1/4
c )
Half kinetic = half potential energy
= 1/4 m ω²x₀²
1/2 m ω²( x₀²- x ² )
x₀²/2 = x₀²- x ²
x² = x₀²/2
x = x₀/√2
Answer:
∆ = 14°
Explanation:
Let the angle be ∆
Opposite = 2.07 m/s
Adjacent = 8.3 m/s
Tan ∆ = opposite / adjacent
Tan ∆ = 2.07 / 8.3
Tan ∆ = 0.2494
∆ = ArcTan (0.2494)
∆ = 14°
The angle from vertical the raindrops make for a person jogging is 14°
