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3 years ago

In which location would a free neutron from a decaying U-235 atom be most likely to cause another atom to go split?

Chemistry

1 answer:

Juliette [100K]3 years ago

8 0

Answer:

The correct answer is option B

B. In a sample of enriched uranium

Explanation:

Nuclear fission is a nuclear reaction whereby large nucleus of an atom is break down into smaller parts lighter nuclei or daughter nuclei and release large amount of energy, due to the large amount of energy there are alot of heat released.

During the process large nucleous is bombarded by the neutrons, as a result of this the nucleous becomes disintegrated because it's unstable and their is production of lighter nuclei as well as neutrons and energy.

When the U -235 particles are compacted together there result a high energy neutron which can bombard another Uranium - 235 molecule in the region. uranium is enriched with more of the fissile uranium isotope, then when it is enriched it can be used to make atomic reactors and explosives like bombs.

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From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

<u>Answer:</u> The concentration of $NH_3$ required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago

The energy required to break existing chemical bonds in reactants is called the ______ energy.

mixer [17]

The energy required to break existing chemical bonds in reactants is called the activation energy.

<h3>What is activation energy?</h3>

Activation energy in chemistry is the energy required to initiate a chemical reaction.

Chemical reactions involve the breaking of chemical bonds in substances called reactants to form new substances called products.

The energy required to break the bond in the existing reactants thus elevating these substances to a state of high activation is known as activation energy.

Therefore, it can be said that energy required to break existing chemical bonds in reactants is called the activation energy.

Learn more about activation energy at: brainly.com/question/11334504

#SPJ1

8 0

2 years ago

Calculate the morality of a 35.4% (by mass) aqueous solution of phosphoric acid (H3PO4). Molar mass of H3PO4 is 98.00g/mol

Butoxors [25]

Answer:

no idea with the answer pls check with otherr

3 0

2 years ago

Name the compound containing only fluorine and hydrogen.

Sonbull [250]

Hydrogen has only one electron. It has one proton of nucleus and one outter electron.

7 0

3 years ago

If a solution is saturated, which of these is true?

Fiesta28 [93]

If a solution is saturated, that means it already posses the maximum number of solutes thus have been dissolved in it, and thus the concentration cannot be increased.

8 0

3 years ago

Read 2 more answers