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daser333 [38]
2 years ago
13

What is the percentage by mass of copper in copper oxide (CuO)?

Chemistry
1 answer:
Viefleur [7K]2 years ago
7 0

Answer:

79.89%

Explanation:

Copper has a molar mass of 63.55

Oxygen has a molar mass of 16.00

If you add these you get 79.55

To get the mass percent of copper divide copper by the whole. 63.55/79.55*100= 79.89%

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100 g of water (specific heat =4.184J/g) and 100g of a metal sample (specific heat = 0.397 J/g) are heated from 25 to 75. Which
Viktor [21]
Q=heat and Q=m*c*dekta(temp)
So we have

Q= 100g*4.184*50=20920J of heat energy

Q= 100g * 0.397* 50= 1985J of heat energy

So the water requires more energy and this is due to the higher heat capacity value of water than the metal sample

Please help me out and rate Brainliest if my answer helped you understand the concept and how to solve!! Any questions please just ask! Thank you so much!!
7 0
3 years ago
A current of 2.50 amps is passed through an electrolytic cell containing a solution of M(NO3)2, where M represents an unidentifi
Elina [12.6K]

Answer:

The chemical symbol will be "_{29}^{63.5}\textrm{Cu}".

Explanation:

The given values are:

Current,

I = 2.50 amps

Time,

t = 2 hr

or,

 = 7200 sec

Metal deposited,

W = 5.93 gm

As we know,

⇒  W=Z\times i\times t

or,

⇒  Z=\frac{W}{i\times t}

On putting the given values, we get

⇒      =\frac{5.93}{2.5\times 7200}

⇒      =3.2945\times 10^{-4}

hence,

⇒ Atomic \ mass=Z\times electrons\times 96500

⇒                       =3.2945\times 10^{-4}\times 2\times 96500

⇒                       =63.5

Thus the above is the right answer.

7 0
3 years ago
The heart has 2 chambers: The UPPER CHAMBERS are called the ______________ and the LOWER CHAMBERS are called the _______________
katovenus [111]

The heart has 2 chambers: The UPPER CHAMBERS are called the <u>atrium</u> and the LOWER CHAMBERS are called the <u>ventricles</u>

Therefore , answer is c

7 0
3 years ago
Read 2 more answers
Using Le Chatelier’s principle, predict which equilibrium system below decrease the concentration of the reactant (H2CO3) as a r
seropon [69]

Answer:

The correct answer is c add more HCO3- by adding NaHCO3.

Explanation:

The reaction mentioned in the question is carried out by bicarbonate buffer system of our body to maintain the normal acid  base balance.

         Now concentration of the reactant (H2C03) is decreased then NaHCO3 should be added which undergo breakdown to release bicarbonate ions(HCO3-).

        The released bicarbonate ions then reacts with H+ to form Carbonic acid(H2CO3).Thus homeostasis of H2CO3 is maintained.

4 0
3 years ago
Read 2 more answers
The ideal gas law equation is: PV = nRT
nignag [31]

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

8 0
2 years ago
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