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3 years ago

Does anyone taste the difference between left and right twix?

Physics

1 answer:

4vir4ik [10]3 years ago

3 0

I personally don't (I can't speak for others tho) but I say right twix is better for the memes

You might be interested in

What is physics and biology

lorasvet [3.4K]

Answer:Biology is the study of living organisms. Physics is the study of matter and the laws of nature to understand the behavior of matter and the universe. The Biophysical Society explains that, when scientists combine physics and biology, they learn more about biological systems on a molecular or atomic level.

Explanation:

8 0

3 years ago

A force of 200N acts between two objects at a certain distance apart .the value of the force when the distance is halved is?

statuscvo [17]

Answer:

800N is the answer

Explanation:

hope it helps

6 0

3 years ago

A 30000 grams boy is riding a merry-go-round with a radius of 600 cm. What is the centripetal force and acceleration on the boy

irga5000 [103]

Answer:

centripetal force is calculated by mass(kg) × tangetial velocity(m/s) ÷ radius (m)

Explanation:

so 30000g= 30kg

50km/h = 13.88m/s

600cm= 6m

30×13.88÷6= 69.4N

N= Newton's

hope this helps.

btw I'm 16 and love physics so I tried my best in this hope it went well!!

7 0

3 years ago

an experiment was done to see which colored sand would heat up the most when placed in the sun. The sand samples were white, red

olga_2 [115]

•Independent: different color sand samples
•Dependent: temperature of the sand
•Control/constant (means the same thing) : Same containers, same time in sun, same thermometer

7 0

3 years ago

The Sun orbits the center of the Milky Way galaxy once each 2.60 × 108 years, with a roughly circular orbit averaging 3.00 × 104

Mamont248 [21]

To solve this problem it is necessary to apply the kinematic equations of linear and angular motion, as well as the given definitions of the period.

Centripetal acceleration can be found through the relationship

$a_c = \frac{v^2}{R}$

Where

v = Tangential Velocity

R = Radius

At the same time linear velocity can be expressed in terms of angular velocity as

$v = R\omega$

Where,

R = Radius

$\omega =$ Angular Velocity

PART A) From this point on, we can use the values used for the period given in the exercise because the angular velocity by definition is described as

$\omega = \frac{2\pi}{T}$

T = Period

So replacing we have to

$\omega = \frac{2\pi}{2.6*10^8years}\\\omega = 2.4166*10^{-8}rad/years\\\omega = 2.4166*10^{-8}rad/years(\frac{1years}{365days})(\frac{1day}{86400s})\\\omega = 7.663*10^{-16}rad/s$

Since $1 Light year = 9.48*10^{15}m$

Then the radius in meters would be

$R = (3*10^4ly)(\frac{9.48*10^{15}m}{1ly})$

$R = 2.844*10^{20}m$

Then the centripetal acceleration would be

$a_c = \frac{v^2}{R}\\a_c = \frac{(R\omega)^2}{R}\\a_c = R\omega^2 \\a_c = 2.844*10^{20}(7.663*10^{-16})^2\\a_c = 1.67*10^{-10}m/s^2$

From the result obtained, considering that it is an unimaginably low value of an order of less than $10^{-10}$ it is possible to conclude that it supports the assertion on the inertial reference frame.

8 0

3 years ago