Question:
A) C6H6
B) CH3CH2CH2CH2CH2COH6
C) NaCl
D) NH3
Answer:
The correct option is;
A) C₆H₆
Explanation:
Heat of fusion = 6.02 kJ/mol
Heat of vaporization =40.8 kJ/mol
Here, we analyze each of the options as follows
A) C₆H₆
Benzene has a melting point of 5.5° C and a boiling point of
80.1 ° C similar to water
Heat of fusion = 9.92 kJ/mol
Heat of vaporization =30.8kJ/mol
B) CH₃CH₂CH₂CH₂CH₂COH₆
The above compound is more likely solid
C) NaCl solid
D) NH₃ melting point = -77.73 °C boiling point = -33.34 °C
Of the above, the compounds the one that closely resembles water is C₆H₆
Answer:
21.3 V, 1.2 A
Explanation:
1.
These resistors are in series, so the net resistance is:
R = R₁ + R₂ + R₃
R = 20 + 30 + 45
R = 95
So the current is:
V = IR
45 = I (95)
I = 9/19
So the voltage drop across R₃ is:
V = IR
V = (9/19) (45)
V ≈ 21.3 V
2.
First, we need to find the equivalent resistance of R₂ and R₃, which are in parallel:
1/R₂₃ = 1/R₂ + 1/R₃
1/R₂₃ = 1/10 + 1/10
R₂₃ = 5
Now we find the overall resistance by adding the resistors in series:
R = R₁ + R₂₃ + R₄
R = 10 + 5 + 10
R = 25
So the current through R₁ is:
V = IR
30 = I (25)
I = 1.2 A
W = F x D
The work you put into a machine -- the input force -- is the force you apply times the distance you apply it. The work done by the machine equals the resisting weight times the distance it moves when you perform the work.
Copper is the second best known electrical conducting substance. The first best one is silver. We almost always use copper because silver costs too much.
Answer:
= 351.84 J
Explanation:
Using the conservation of energy K:
![E_i = E_f](https://tex.z-dn.net/?f=E_i%20%3D%20E_f)
so:
![\frac{1}{2}mv^2 = K_f + mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20K_f%20%2B%20mgh)
where m is the mass, v the initial velocity,
is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.
Then, replacing values, we get:
![\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%281.2kg%29%2830m%2Fs%29%5E2%20%3D%20K_f%20%2B%20%281.2kg%29%289.8m%2Fs%5E2%29%2816m%29)
solving for
:
= 351.84 J