Answer:
9.0 m
Explanation:
Let the initial velocity be 'u'.
Given:
Final velocity is half of initial velocity.
Maximum height reached by ball (H) = 12.0 m
Acceleration of the ball is due to gravity (g) = -9.8 m/s²(Downward)
Now, first, we will find initial velocity of the ball using equation of motion given as:
For maximum height, final velocity is 0 as the ball stops at the maximum height temporarily. So, 
Also, 
Now, plug in all the values and solve for 'u'.
Now, consider the motion of the ball till the velocity reaches half of initial velocity.
So, final velocity (v) = 
Now, again using the same equation and finding the new height now. Let the new height be 'h'.
So, equation of motion is given as:
Therefore, the height reached by the ball when velocity is decreased to one-half of the initial velocity is 9.0 m.
Answer:
Twice as fast
Explanation:
Solution:-
- The mass of less massive cart = m
- The mass of Massive cart = 2m
- The velocity of less massive cart = u
- The velocity of massive cart = v
- We will consider the system of two carts to be isolated and there is no external applied force on the system. This conditions validates the conservation of linear momentum to be applied on the isolated system.
- Each cart with its respective velocity are directed at each other. And meet up with head on collision and comes to rest immediately after the collision.
- The conservation of linear momentum states that the momentum of the system before ( P_i ) and after the collision ( P_f ) remains the same.
- Since the carts comes to a stop after collision then the linear momentum after the collision ( P_f = 0 ). Therefore, we have:
- The linear momentum of a particle ( cart ) is the product of its mass and velocity as follows:
m*u - 2*m*v = 0
Where,
( u ) and ( v ) are opposing velocity vectors in 1-dimension.
- Evaluate the velcoity ( u ) of the less massive cart in terms of the speed ( v ) of more massive cart as follows:
m*u = 2*m*v
u = 2*v
Answer: The velocity of less massive cart must be twice the speed of more massive cart for the system conditions to hold true i.e ( they both come to a stop after collision ).
The tree might get swept away by the current and it will disappear when it catches on something
Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x 
N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x 
J
proton's mass, m = 1.673 x 
kg
charge, q = 1.602 x 
C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x J) / (1.602 x C)(2 m)
= 1.01 x N/C
