Answer:
M = 1433.5 kg
Explanation:
This exercise is solved using the Archimedean principle, which states that the hydrostatic thrust is equal to the weight of the desalinated liquid,
B = ρ g V
with the weight of the truck it is in equilibrium with the push, we use Newton's equilibrium condition
Σ F = 0
B-W = 0
B = W
body weight
W = M g
the volume is
V = l to h
rho_liquid g (l to h) = M g
M = rho_liquid l a h
we calculate
M = 1000 4.7 6.10 0.05
M = 1433.5 kg
16, 5 , 3 = 16+5+3= 24 + 3
So at the end put 24 + 3 cm
And put 16 for the lengths
For the value 5 and for the diving thingy 3
A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
it is the point at infinity where it is at a distance from the curve equal to the radius of curvature lying on the normal vector. Sorry no diagram
Answer:
55
Explanation:
I hope this answer help u