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2 years ago

Electrons are modeled using a "cloud" around the nucleus because they

Physics

2 answers:

LenaWriter [7]2 years ago

7 0

Explanation:

It is known that an atom consists of three sub-atomic particles, that is, protons, neutrons, and electrons.

Protons and neutrons are located inside the nucleus of the atom whereas electrons revolve around the nucleus of the atom forming a cloud of electrons.

These electrons occupy orbits of their respective energy levels.

Therefore, we can conclude that electrons are modeled using a "cloud" around the nucleus because they revolve around the nucleus.

taurus [48]2 years ago

4 0

An electron cloud is a visual model of the most probable locations of electrons in a atom. The cloud is denser where you will probably find a electron.

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Radda [10]

E = mc^2
m = e/c^2
m = 2.7*10^16/(300000^2)
m = 300000

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3 years ago

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jasenka [17]

Answer:

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Explanation:

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2 years ago

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Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis

WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

$F=G\frac{Mm}{r^{2}}$ (1)

Where:

$F$ is the gravitational force between Earth and Moon

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$M=5.972(10)^{24} kg$ is the mass of the Earth

$m=7.349(10)^{22} kg$ is the mass of the Moon

$r=3.9(10)^{8} m$ is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to $F$ :

$F=m.a_{C}$ (2)

Where $a_{C}$ is the centripetal acceleration given by:

$a_{C}=\frac{V^{2}}{r}$ (3)

Being $V$ the orbital velocity of the moon

Making (1)=(2):

$m.a_{C}=G\frac{Mm}{r^{2}}$ (4)

Simplifying:

$a_{C}=G\frac{M}{r^{2}}$ (5)

Making (5)=(3):

$\frac{V^{2}}{r}=G\frac{M}{r^{2}}$ (6)

Finding $V$ :

$V=\sqrt{\frac{GM}{r}}$ (7)

$V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}}$ (8)

Finally:

$V=1010.92 m/s$

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2 years ago

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kumpel [21]

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2 years ago

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Bas_tet [7]

Answer:

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2 years ago