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nlexa [21]
2 years ago
10

Which feature forms when magma cools beneath Earth's surface?

Chemistry
2 answers:
snow_lady [41]2 years ago
6 0
I believe that the answer is Calderas
Snowcat [4.5K]2 years ago
4 0
I’m pretty sure it’s Calderas
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21+ Cl2 → 12+201 -
Alina [70]

Answer:

\rm 2\; I^{-} + Cl_2 \to I_2 + 2 \; Cl^{-}.

Start color: yellowish-green.

End color: dark purple.

Assumption: no other ion in the solution is colored.

Explanation:

In this reaction, chlorine gas \rm Cl_2 oxidizes iodine ions \rm I^{-} to elemental iodide \rm I_2. At the same time, the chlorine atoms are converted to chloride ions \rm Cl^{-}.

Fluorine, chlorine, bromine, and iodine are all halogens. They are all found in the 17th column of the periodic table from the left. One similarity is that their anions are not colored. However, their elemental forms are typically colored. Besides, moving down the halogen column, the color becomes darker for each element.

Among the reactants of this reaction, \rm I^{-} is colorless. If there's no other colored ion, only the yellowish-green hue of \rm Cl_2 would be visible. Hence the initial color of the reaction would be the yellowish-green color of \rm Cl_2.

Similarly, among the products of this reaction, \rm Cl^{-} is colorless. If there's no other colored ion, only the dark purple hue of \rm I_2 would be visible. Hence the initial color of the reaction would be the dark purple color of \rm I_2.

5 0
3 years ago
3. If 90.0 grams of barium chloride react with sulfuric acid, how many
PtichkaEL [24]

Answer:

The answer to your question is 100.8 g

Explanation:

Data

  mass of Barium chloride = 90 g

  mass of Barium sulfate = ?

Balanced chemical reaction

    BaCl₂  +  H₂SO₄   ⇒    BaSO₄  +  2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g

2.- Use proportions to find the mass of BaSO₄

              208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

                90 g of BaCl₂    ---------------------   x

                              x = (90 x 233.3) / 208.3

                              x = 20997/ 208.3

                              x = 100.8 g

3.- Conclusion

There will be produced 100.8 g of BaSO₄          

4 0
2 years ago
HELP ME<br>dm me on insta<br>temi.awolola<br>I need a lot of help ​
Georgia [21]

Protons:

- Have a mass

- Positively charged

- Found inside the nucleus of an atom

Electrons:

- Have a mass. (9.10938188×10−31 kilograms), though this can sometimes be considered negligible due to how small that actually is. Barely factored into atomic mass

- Negatively charged

- Found outside the nucleus in the electron shell

Neutrons:

- Have a mass

- Neutral (no charge)

- Found inside the nucleus of an atom

Atom A:

- 1 proton

- 0 Neutrons

- 1 electron

- Atomic mass of 1

- Atomic number of 1

Atom B:

- 8 Protons

- 10 Neutrons

- 8 electrons

- Atomic mass of 18

- Atomic number of 8

Atomic mass includes the number of protons and neutrons in the nucleus. Atomic number is the number of protons, as this is what defines what type of element the atom is.

6 0
2 years ago
Waste water from nuclear power plants is generally
FrozenT [24]

Answer:

waste water from nuclear power plant is

generally very harmful for our environment

and for everyone

hope it will help

4 0
3 years ago
How many milligrams of magnesium reacts with excess HCl to produce 31.2 mL of hydrogen gas at 754 Torr and 25.0℃.
Ivanshal [37]

Answer:

There will react 30.9 milligrams of magnesium

Explanation:

Step 1: Data given

Volume of hydrogen = 31.2 mL

Pressure = 754 torr = 754/760 = 0.992 atm

Temperature = 25.0 °C = 298 Kelvin

Step 2: The balanced equation

Mg + 2HCl → MgCl2 + H2

Step 3: Calculate moles of H2

p*V = n*R*T

⇒ with p = the pressure of H2 = 0.992 atm

⇒with V = the volume of H2 = 31.2 mL = 0.0312 L

⇒ with n = the moles of H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T= the temperature = 25.0 °C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.992*0.0312)/(0.08206*298)

n = 0.00127 moles

Step 4: Calculate moles of Mg

For 1 mol of Mg we need 2 moles of HCl to produce 1 mol of MgCl2 and 1 mol of H2

For 0.00127 moles of H2 we need 0.00127 moles of Mg

Step 5: Calculate mass of Mg

Mass of Mg = moles of Mg * molar mass of Mg

Mass of Mg = 0.00127 moles * 24.3 g/mol

Mass of Mg = 0.0309 grams = 30.9 mg of Mg

There will react 30.9 milligrams of magnesium

3 0
3 years ago
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