All categories

4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Physics

2 answers:

Vsevolod [243]4 years ago

8 0

Explanation :

Resultant of two vectors can be find out by adding two vectors together. We have two vectors $\underset{a}{\rightarrow}$ in up direction and $\underset{b}{\rightarrow}$ in right.

There resultant can be given by $\underset{R}{\rightarrow}$ , which is the sum of two vectors.

So, diagram (3) shows correct answer.

natka813 [3]4 years ago

5 0

Your answer lies in between Diagram 3 and Diagram 4. You would add the sum of the two vectors to get your resultant, in which your answer comes out to be Diagram 3. ♥

You might be interested in

17.

avanturin [10]

Answer:

Gamma rays

Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.

Explanation:

6 0

3 years ago

Please help asap asap<br> wdtwygcbhyeegdlu tcgbihjlnkdm;fnbkhjg hv

kicyunya [14]

Answer:

Explanation:

Bbbb

6 0

3 years ago

Does a feather fall as fast as a rock in a vacuum? If so why?

7nadin3 [17]

Answer:

No.

Explanation:

A feather is less dense and thus less force exerted while a rock is very dense thus exerting more force .

3 0

3 years ago

The direction of an electric field is the direction (5 points)

vlabodo [156]

The direction of an electric field is determined from the behavior of a positive test charge that is set free in the electric field.This charge moves along a distinct vector showing the direction of the electric field Therefore the answer is b. a positive charge will move in the field.

5 0

3 years ago

A car with mass 950 kg and a speed of 16 m/s approaches an intersection. A 1300 kg minivan traveling at 21 m/s is heading for th

Alex73 [517]

Answer:

$V_f = 13.8863 \angle 60.89\°$

Explanation:

Our values are,

$m_1 = 950Kg\\v_1 = 16m/s \\m_2 =1300Kg\\v_2 = 21m/s$

We have all the values to apply the law of linear momentum, however, it is necessary to define the two lines in which the study will be carried out. Being an intersection the vehicle of mass m_1 approaches through the X axis, while the vehicle of mass m_2 approaches by the y axis. In the collision equation on the X axis, we despise the velocity of object 2, since it does not come in this direction.

$m_1v_1=(m_1+m_2)v_fcos\theta$

For the particular case on the Y axis, we do the same with the speed of object 1.

$m_2v_2=(m_1+m_2)v_fsin\theta$

By taking a final velocity as a component, we can obtain the angle between the two by relating the equations through the tangent

$Tan\theta = \frac{m_2v_2}{m_1v_1}\\Tan\theta = \frac{1300*21}{950*16}\\\theta = tan^{-1}(1.7960)\\\theta = 60.89\°$

Replacing in any of the two functions, given above, we will find the final speed after the collision,

$(950)(16)=(950+1300)V_fcos(60.89)$

$V_f= \frac{(950)(16)}{(950+1300)cos(60.89)}$

$V_f = 13.8863 \angle 60.89\°$

8 0

3 years ago