Question

A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

Answer 1

Answer:

The work done by gravity is $4.975 \: Joules$

Explanation:

The data given in the question is :

Mass is $0.245 kg$

Height from ground is $2.07 m$

As we know , the work done is state function , it depends on initial and final position not on the path followed.

So, work done by gravity = change in potential energy

Work done = Initial potential energy - final potential energy

Insert values from question

Work done = $mass \times gravity \times (change \: in \: height)$

Work done = $0.245 kg \times 9.81 m/s^{2} \times 2.07 m$

So, work done = $4.975 Joules$

Hence the work done by gravity is $4.975 \: Joules$