<h2>precipitation reactions</h2>
α prєcípítαtíσn rєαctíσn rєfєrs tσ thє fσrmαtíσn σf αn ínsσluвlє sαlt whєn twσ sσlutíσns cσntαíníng sσluвlє sαlts αrє cσmвínєd. thє ínsσluвlє sαlt thαt fαlls σut σf sσlutíσn ís knσwn αs thє prєcípítαtє, hєncє thє rєαctíσn's nαmє. prєcípítαtíσn rєαctíσns cαn hєlp dєtєrmínє thє prєsєncє σf vαríσus íσns ín sσlutíσn.
Answer: B
Im not sure, if i am right then mark as brainiest please (:
Answer:
The answer, because i gotta
Explanation:
finish a challenge
To obtain an acceleration northward is necessary than the west component of the first cable and the east component of the second cable be equal, otherwise the barge will head northwest or northeast.
So for the first cable the component to west is:
Fw = F1 * cos (30Âş) = 80*cos(30Âş)
And for the second cable the component to east is:
Fe = F2 * cos (20Âş) = F2*cos(20Âş)
Then to get a movement northward we need than Fw = Fe, so:
80*cos(30Âş) = F2*cos(20Âş)
F2 = 80*cos(30Âş)/cos(20Âş)
F2 = 73.73 N So the magnitude of the east cable should be 73.73 Newtons
