Answer:
The time it took the bobsled to come to rest is 10 s.
Explanation:
Given;
initial velocity of the bobsled, u = 50 m/s
deceleration of the bobsled, a = - 5 m/s²
distance traveled, s = 250 m
Apply the following kinematic equation to determine the time of motion of the bobsled;
s = ut + ¹/₂at²
250 = 50t + ¹/₂(-5)t²
250 = 50t - ⁵/₂t²
500 = 100t - 5t²
100 = 20t -t²
t² - 20t + 100 = 0
t² -10t - 10t + 100 = 0
t (t - 10) - 10(t - 10) = 0
(t - 10)(t - 10) = 0
t = 10 s
Therefore, the time it took the bobsled to come to rest is 10 s.
Answer:
50 KeV
Explanation:
50 KeV will be the most likely initial interaction with tissue.
Because Higher the energy lesser will the interaction with tissues, Because it will penetrate through tissue more easily in a very lesser time Whereas the photon with least energy will take more time to penetrate through the tissue, hence, higher interaction with tissue.
The weight of the heavier player bakes it a lot harder to push him or do work because of the net force gravity<span />
What part of the bacterial cell helps it stick to surfaces
