Explanation:
Teniendo en cuenta los numeros de oxidacion negativos de cada uno
P:fosforo(-3)
S:Azufre (-2)
Br:Bromo (-1)
Y el H: hidrogeno con una valencia
positiva de +1
los compuesto que se formaran son los siguientes
1 H3P= fosfuro de hidrogeno
2 H2S= sulfuro de hidrogeno
3 HBr= Acido bromhidrico
ESPERO ABERTE AYUDADO ;D
The relative charge of a proton is +1. The relative mass of a proton is 1. The location of a proton is in the nucleus of an atom.
Hope this helps!
No it is not
hope this helped
Answer:

Explanation:
You don't give the reaction, but we can get by just by balancing atoms of Na.
We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
M_r: 142.04
2NaOH + … ⟶ Na₂SO₄ + …
n/mol: 0.75
1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.
Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH
= 0.375 mol Na₂SO₄
2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.
Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄
The reaction produces
of Na₂SO₄.