Answer:
Volume of hydrogen gas = 0.1539dm3
Explanation:
Equation of the reaction
Mg(s) + 2HCl --> MgCl2(aq) + H2(g)
Molar concentration of HCl = 0.2mol/dm3
Mass of magnesium = 0.0243g
Volume of HCl = 0.05dm3
No of moles of HCl = Volume * molar concentration
= 0.05 * 0.5
= 0.01mol
No of moles of Magnesium = mass/molecular weight
Molecular weight of Magnesium = 24g/mol
No of moles of magnesium = 0.0243/24
= 0.001013mol
Using stoichiometry,
Since 1 mole of Magnesium metal reacted with 2 moles of HCl acid
HCl is the limiting reagent.
Therefore, 1 mole of hydrogen gas is given off.
0.005 mole of hydrogen is given off.
Using ideal gas law, PV = nRT
Volume = (0.005 * 0.0821 * 300)/0.8
= 0.1539dm3
